Jinja2 check if value exists in list of dictionaries

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If possible, I would move this logic to the python part of the script before rendering it in Jinja. Because, as stated in the Jinja documentation: "Without a doubt you should try to remove as much logic from templates as possible."

any([person['role'] == 'admin' for person in person_dict_list]) is a lot easier to follow at first glance than the other 2 options.

If that's not an option, I would probably use the first, build in function, because I think it's less prone to errors in edge cases as your own solution, and is about 6x less code.

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mrroot5
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mrroot5

Full Stack developer, in love with JavaScript and Python, specially Django, with a high motivation ratio

Updated on July 21, 2022

Comments

  • mrroot5
    mrroot5 almost 2 years

    I am trying to check if a value exists inside a list with dictionaries. I use flask 1.0.2. See example below:

    person_list_dict = [
        {
            "name": "John Doe",
            "email": "[email protected]",
            "rol": "admin"
        },
        {
            "name": "John Smith",
            "email": "[email protected]",
            "rol": "user"
        }
    ]
    

    I found two ways to solve this problem, can you tell me which is better?:

    First option: jinja2 built-in template filter "map"

    <pre>{% if "admin" in person_list_dict|map(attribute="rol") %}YES{% else %}NOPE{% endif %}</pre>
    # return YES (john doe) and NOPE (john smith)
    

    Second option: Flask template filter

    Flask code:

    @app.template_filter("is_in_list_dict")
    def is_any(search="", list_dict=None, dict_key=""):
        if any(search in element[dict_key] for element in list_dict):
            return True
        return False
    

    Template code:

    <pre>{% if "admin"|is_in_list_dict(person_list_dict, "rol") %} YES {% else %} NOPE {% endif %}</pre>
    # return YES (john doe) and NOPE (john smith)
    

    Thanks :-).

  • mrroot5
    mrroot5 over 5 years
    I prefer the first options because it is developed by jinja and, as you say, it requires less code. Thanks Joost :-).
  • Luke Pighetti
    Luke Pighetti over 4 years
    Whenever I try to do this I keep getting the error TemplateSyntaxError: expected token ',', got 'for', any ideas what I'm doing wrong?
  • timle
    timle over 2 years
    Luke: The above example is meant to run in Python, before passing the list to Jinja. It will not run in Jinja.