JQuery fadeOut(function(){fadeIn});

Question

I have a problem with my webpage. I have 4 div's which should all fade in after the one before fades out. The code I use is:

$('.btn').click(function(){
    $('#box3').delay(5000).fadeOut('slow', function(){
        $('#box4').fadeIn('slow');
    });
});

With #box1 > #box2 it works, with #box2 > #box3 it works but when I try to go from #box3 > #box4 sometimes #box3 fades out then fades in with #box4. I have No idea why it is doing this.

Thanks,

http://jsfiddle.net/chLRa/4/ now working. Sometimes when going from 3 to 4 it still fades in 3 and 4

Solution 1

Here's a simple helper function to help you do this.

function fade(thisIn, callback){
    boxes.not(thisIn).filter(':visible').delay(5000).fadeOut('slow', function(){
        thisIn.fadeIn('slow', callback);
    });
}

jsFiddle

Solution 2

I'd say try using finish() method:

$('.btn').click(function(){
    $('#box3').finish().delay(5000).fadeOut('slow', function(){
        $('#box4').fadeIn('slow');
    });
});

Maybe would be better in your case to use it after delay()

Comments

[codedme]

finish method has been added from 1.9 stop(true,true) can be used in previous versions

[Karl-André Gagnon]

@KevinB same, but i don't really get the difference with stop. Is it the same thing?

[codedme]

.finish() also causes the CSS property of all queued animations to jump to their end values, as well.api.jquery.com/finish

[Admin]

Thanks but that didn't work, now the delay doesn't work on #box4 and #box3 still fades in after the delay.

[Admin]

I have made it so that every box has a separate button to fadeout itself and fadein the next one. This way they all fadeOut fadeIn with only one button

[DevlshOne]

My solution only has one button, as well. Did you look at my fiddle?

[Admin]

My site has 1 button every box, total 4 buttons. Every button fades in another div. I have updated my fiddle with a working example