Linq to XML, select all attributes and their values for a given node
12,098
Solution 1
Update
Summarized in a method:
public IEnumerable<XAttribute> GetAttributes(string modelName, string colour)
{
XDocument mappings = XDocument.Load(@"D:\colour_mappings.xml");
var q1 =
from elm in mappings.Descendants("model")
where (string)elm.Attribute("name") == "modelY"
select elm;
var q2 =
from elm in q1.Descendants("mapping")
where (string)elm.Attribute("colour") == "White"
select elm.Attributes().Where(a => a.Name != "colour");
foreach (IEnumerable<XAttribute> attributeList in q2)
{
foreach (XAttribute attribute in attributeList)
{
yield return attribute;
}
}
}
Solution 2
as I am pushed for time I will use a 2 stage process
But would be interested to hear if this is possible in one query
var matchingModelXml = from c in mappings.Descendants("model")
where (string)c.Attribute("name") == "modelY"
select c;
var mappingAttributes = from b in matchingModelXml.Descendants("mapping")
where (string)b.Attribute("colour") == "White"
select b.Attributes();
Solution 3
Just because I like a challenge, here it is in one query:
XDocument test = XDocument.Parse("<colourMappings> <model name=\"modelX\"> <mapping colour=\"White\" configCode=\"1\"></mapping> <mapping colour=\"Aluminium\" configCode=\"2\"></mapping> <mapping colour=\"Black\" configCode=\"3\"></mapping> <mapping colour=\"Blue\" configCode=\"4\"></mapping> <mapping colour=\"White Pearl\" configCode=\"5\"></mapping> <mapping colour=\"Graphite\" configCode=\"6\"></mapping> <mapping colour=\"Gunmetal\" configCode=\"7\"></mapping> <mapping colour=\"Indigo\" configCode=\"8\"></mapping> <mapping colour=\"Red\" configCode=\"9\"></mapping> </model> <model name=\"modelY\"> <mapping colour=\"White\" configCode=\"1\" stConfigCode= \"xx\" dgConfigCode=\"hj\"></mapping> <mapping colour=\"Aluminium\" configCode=\"2\" stConfigCode= \"xy\" dgConfigCode=\"gh\"></mapping> <mapping colour=\"Black\" configCode=\"3\" stConfigCode= \"xt\" dgConfigCode=\"fg\"></mapping> <mapping colour=\"Blue\" configCode=\"4\" stConfigCode= \"sd\" dgConfigCode=\"fg\"></mapping> <mapping colour=\"White Pearl\" configCode=\"5\" stConfigCode= \"df\" dgConfigCode=\"df\"></mapping> <mapping colour=\"Graphite\" configCode=\"6\" stConfigCode= \"xc\" dgConfigCode=\"df\"></mapping> <mapping colour=\"Gunmetal\" configCode=\"7\" stConfigCode= \"cv\" dgConfigCode=\"cv\"></mapping> <mapping colour=\"Indigo\" configCode=\"8\" stConfigCode= \"zx\" dgConfigCode=\"vb\"></mapping> <mapping colour=\"Red\" configCode=\"9\" stConfigCode= \"fg\" dgConfigCode=\"cv\"></mapping> </model></colourMappings>");
var maps = from model in test.Root.Elements("model")
from attr in model.Attributes("name")
from mapping in model.Elements("mapping")
where attr.Value == "modelY" && mapping.Attribute("colour").Value == "White"
select new
{
configCode = mapping.Attribute("configCode").Value
, stConfigCode = mapping.Attribute("stConfigCode").Value
, dgConfigCode = mapping.Attribute("dgConfigCode").Value
};
foreach (var map in maps)
{
Console.Write("configCode: ");
Console.WriteLine(map.configCode);
Console.Write("stConfigCode: ");
Console.WriteLine(map.stConfigCode);
Console.Write("dgConfigCode: ");
Console.WriteLine(map.dgConfigCode);
}
Author by
ChrisCa
Updated on June 05, 2022Comments
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ChrisCa almost 2 years
I have an xml mapping file that looks something like this
<colourMappings> <model name="modelX"> <mapping colour="White" configCode="1"></mapping> <mapping colour="Aluminium" configCode="2"></mapping> <mapping colour="Black" configCode="3"></mapping> <mapping colour="Blue" configCode="4"></mapping> <mapping colour="White Pearl" configCode="5"></mapping> <mapping colour="Graphite" configCode="6"></mapping> <mapping colour="Gunmetal" configCode="7"></mapping> <mapping colour="Indigo" configCode="8"></mapping> <mapping colour="Red" configCode="9"></mapping> </model> <model name="modelY"> <mapping colour="White" configCode="1" stConfigCode= "xx" dgConfigCode="hj"></mapping> <mapping colour="Aluminium" configCode="2" stConfigCode= "xy" dgConfigCode="gh"></mapping> <mapping colour="Black" configCode="3" stConfigCode= "xt" dgConfigCode="fg"></mapping> <mapping colour="Blue" configCode="4" stConfigCode= "sd" dgConfigCode="fg"></mapping> <mapping colour="White Pearl" configCode="5" stConfigCode= "df" dgConfigCode="df"></mapping> <mapping colour="Graphite" configCode="6" stConfigCode= "xc" dgConfigCode="df"></mapping> <mapping colour="Gunmetal" configCode="7" stConfigCode= "cv" dgConfigCode="cv"></mapping> <mapping colour="Indigo" configCode="8" stConfigCode= "zx" dgConfigCode="vb"></mapping> <mapping colour="Red" configCode="9" stConfigCode= "fg" dgConfigCode="cv"></mapping> </model> </colourMappings>
I want to be able to pull out all the attributes and their values given a model name and colour
e.g.
given ModelY and White, I'd like to get configCode="1" stConfigCode= "xx" dgConfigCode="hj" This could be in any structure - array, list, whatever
I have been using Linq to XML but can't get the correct syntax
XDocument mappings = XDocument.Load(@"D:\colour_mappings.xml"); var q = from c in mappings.Descendants("model") where (string)c.Attribute("name") == "modelY" && (string)c.Descendants("mapping").Attributes("colour").FirstOrDefault() == "White" select c.Attributes();
anyone know how to do this?
Happy to use any method, doesn't necessarily need to be Linq
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ChrisCa almost 14 yearsthanks - that's not exactly what I need though. Your one returns all the attributes of every mapping I just want the attributes for the single mapping in ModelY that has a colour of white Decieded to do it as a 2 stage query - see below
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Martin Ingvar Kofoed Jensen almost 14 years@Christo Fur: Sorry, my mistake, just updated the code so it should work now :)
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ChrisCa almost 14 yearsthanks - I came to the same conclusion as you and did it in 2 steps
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Martin Ingvar Kofoed Jensen almost 14 yearsThere is a way to do nested queries, but the code gets more complex, so I think this is the better solution
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Martin Ingvar Kofoed Jensen almost 14 yearsNice :) Only need to remove the attribute 'colour', but thats easy :)
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Martin Ingvar Kofoed Jensen almost 14 yearsJust did some timings and it seems that your single query is 50-60% slower on this small sample set. I think the reason is that those 4 "from's" results in a lot of enumerating. But still a nice query :)
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Matt Ellen almost 14 yearsThanks. I probably should have mentioned that I only wrote this for fun. I'd go the two query route too. It's easier to read as well as being faster :)
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Matt Ellen almost 14 yearsI've fiddled with the linq, so it should be a bit quicker, but still not as fast as 2 queries.