Load external xml file?
26,829
Solution 1
Procedurally, simple_xml_load_file.
$file = '/path/to/test.xml';
if (file_exists($file)) {
$xml = simplexml_load_file($file);
print_r($xml);
} else {
exit('Failed to open '.$file);
}
You may also want to consider using the OO interface, SimpleXMLElement.
Edit: If the file is at some remote URI, file_exists
won't work.
$file = 'http://example.com/text.xml';
if(!$xml = simplexml_load_file($file))
exit('Failed to open '.$file);
print_r($xml);
Solution 2
You can use simplexml_load_file
Solution 3
$xml = simplexml_load_file('path/to/file');
Author by
Richard Hedges
Updated on January 29, 2020Comments
-
Richard Hedges over 4 years
I have the following code (from a previous question on this site) which retrieves a certain image from an XML file:
<?php $string = <<<XML <?xml version='1.0'?> <movies> <movie> <images> <image type="poster" url="http://cf1.imgobject.com/posters/b7a/4bc91de5017a3c57fe00bb7a/i-am-legend-original.jpg" size="original" width="675" height="1000" id="4bc91de5017a3c57fe00bb7a"/> <image type="poster" url="http://cf1.imgobject.com/posters/b7a/4bc91de5017a3c57fe00bb7a/i-am-legend-mid.jpg" size="mid" width="500" height="741" id="4bc91de5017a3c57fe00bb7a"/> <image type="poster" url="http://cf1.imgobject.com/posters/b7a/4bc91de5017a3c57fe00bb7a/i-am-legend-cover.jpg" size="cover" width="185" height="274" id="4bc91de5017a3c57fe00bb7a"/> </images> </movie> </movies> XML; $xml = simplexml_load_string($string); foreach($xml->movie->images->image as $image) { if(strcmp($image['size'],"cover") == 0) echo $image['url']; } ?>
What I'd like to know is, how can I load the external XML file rather than writing the XML data in the actual PHP like is shown above?