map iterator in template function unrecognized by compiler

10,474

You need the typename keyword:

for (typename std::map<key,val>::iterator it = map.begin(); #line 13 referenced by gcc
  it!=map.end(); ++it){

See also: Why do we need typename here?

This is because you are in a template definition and iterator is a dependent name. This has been asked before.

g++ "is not a type" error

C++ Template: 'is not derived from type'

Trouble with dependent types in templates

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Eli
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Eli

Updated on June 04, 2022

Comments

  • Eli
    Eli almost 2 years

    I have the following code.

    template<class key,class val>
    bool has_key(key chkey,std::map<key,val> map){
      for (std::map<key,val>::iterator it = map.begin(); #line 13 referenced by gcc
          it!=map.end(); ++it){
        if(chkey == it->first) return true;
      }
      return false;
    }
    

    GCC is giving me the following error.

    objects.hpp: In function `bool has_key(key, std::map<key, val, std::less<_Key>,
      std::allocator<std::pair<const _Key, _Tp> > >)':
    objects.hpp:13: error: expected `;' before "it"
    objects.hpp:14: error: `it' was not declared in this scope
    

    Somehow "it" is not being initialized, what in Sam Hain is going on here?!