MD5 HMAC With OpenSSL

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The third and fifth parameters to HMAC are just wrong. You have to pass the length of the key and the length of data. In your example, this is respectively 64 and 84, not 32 and 28.

So :

-    result = HMAC(EVP_md5(), key, 32, data, 28, NULL, NULL);                                                                                                                                                                         
+    result = HMAC(EVP_md5(), key, 64, data, 84, NULL, NULL); 

With this modification, it seems to be working fine.

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Updated on June 13, 2022

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  • Admin
    Admin almost 2 years

    I was trying to generate MD5 HMAC with OpenSSL & most of the code is borrowed. The hmac being generate is incorrect:

    #include <openssl/hmac.h>
    #include <openssl/evp.h>
    #include <syslog.h>
    #include <string.h>
    
    #include <openssl/engine.h>
    #include <openssl/hmac.h>
    #include <openssl/evp.h>
    #include <stdio.h>
    #include <string.h>
    #include <stdlib.h>
    
    int main() 
    {
      unsigned char* key = (unsigned char*) "2012121220121212201212122012121220121212201212122012121220121212";
      unsigned char* data = (unsigned char*) "johndoejohndoejohndoejohndoejohndoejohndoejohndoejohndoejohndoejohndoejohndoejohndoe";
      unsigned char* expected = (unsigned char*) "abcd1d87dca34f334786307d0da4fcbd";
      unsigned char* result;
      // unsigned int result_len = 16;
      unsigned int result_len = 16;
      int i;
      static char res_hexstring[32];
    
      // result = HMAC(EVP_sha256(), key, 4, data, 28, NULL, NULL);
      result = HMAC(EVP_md5(), key, 32, data, 28, NULL, NULL);
      for (i = 0; i < result_len; i++) {
        sprintf(&(res_hexstring[i * 2]), "%02x", result[i]);
      }
    
      if (strcmp((char*) res_hexstring, (char*) expected) == 0) {
        printf("Test ok, result length %d\n", result_len);
      } else {
        printf("Got %s instead of %s\n", res_hexstring, expected);
      }
    }
    

    The hash being produced is incorrect. I would appreciate some feedback or someone pointing me in the right direction.