Mongodb: Perform a Date range query from the ObjectId in the mongo shell

14,831

Solution 1

You can do that in 2 steps:

 var objIdMin = ObjectId(Math.floor((new Date('1990/10/10'))/1000).toString(16) + "000
0000000000000")
 var objIdMax = ObjectId(Math.floor((new Date('2011/10/22'))/1000).toString(16) + "000
    0000000000000")
 db.myCollection.find({_id:{$gt: objIdMin, $lt: objIdMax}})

or in one step (what is less readable):

db.myCollection.find({_id:{$gt: ObjectId(Math.floor((new Date('1990/10/10'))/1000).toString(16) + "000
    0000000000000"), $lt: ObjectId(Math.floor((new Date('2011/10/10'))/1000).toString(16) + "000
    0000000000000")}})

Solution 2

using mongo shell:

you can use the ObjectId.fromDate built in method:

db.mycollection.find({_id: {$gt: ObjectId.fromDate( new Date('2017-09-23') ) } });

from Node.js driver:

you can use the solution provided by @jksdua here as follows:

db.mycollection.find({_id: {$gt: ObjectID.createFromTime( Date.now()/1000 ) } });
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sc28
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sc28

Updated on June 07, 2022

Comments

  • sc28
    sc28 almost 2 years

    I have a collection that looks like this:

    {
      _id: ObjectId("50a68673476427844b000001"),
      other fields
    }
    

    I want to do a range query to find records between two dates. I know that I can get the date from the ObjectId in the mongo shell var doing this:

    var aDate = ObjectId().getTimestamp()
    

    but there isn't a way (as far as I can figure out at the moment) to create an ObjectId consisting of just the timestamp portion - I think my ideal solution is non-functioning mongo shell code would be:

    var minDate = ObjectId(new Date("2012-11-10"));
    var maxDate = ObjectId(new Date("2012-11-17"));
    

    Use the find with the minDate and MaxDate as the range values.

    Is there a way to do this in the SHELL - I'm not interested in some of the driver products.