Mongodb: Perform a Date range query from the ObjectId in the mongo shell
Solution 1
You can do that in 2 steps:
var objIdMin = ObjectId(Math.floor((new Date('1990/10/10'))/1000).toString(16) + "000
0000000000000")
var objIdMax = ObjectId(Math.floor((new Date('2011/10/22'))/1000).toString(16) + "000
0000000000000")
db.myCollection.find({_id:{$gt: objIdMin, $lt: objIdMax}})
or in one step (what is less readable):
db.myCollection.find({_id:{$gt: ObjectId(Math.floor((new Date('1990/10/10'))/1000).toString(16) + "000
0000000000000"), $lt: ObjectId(Math.floor((new Date('2011/10/10'))/1000).toString(16) + "000
0000000000000")}})
Solution 2
using mongo shell:
you can use the ObjectId.fromDate built in method:
db.mycollection.find({_id: {$gt: ObjectId.fromDate( new Date('2017-09-23') ) } });
from Node.js driver:
you can use the solution provided by @jksdua here as follows:
db.mycollection.find({_id: {$gt: ObjectID.createFromTime( Date.now()/1000 ) } });
sc28
Updated on June 07, 2022Comments
-
sc28 almost 2 years
I have a collection that looks like this:
{ _id: ObjectId("50a68673476427844b000001"), other fields }
I want to do a range query to find records between two dates. I know that I can get the date from the ObjectId in the mongo shell var doing this:
var aDate = ObjectId().getTimestamp()
but there isn't a way (as far as I can figure out at the moment) to create an ObjectId consisting of just the timestamp portion - I think my ideal solution is non-functioning mongo shell code would be:
var minDate = ObjectId(new Date("2012-11-10")); var maxDate = ObjectId(new Date("2012-11-17"));
Use the find with the minDate and MaxDate as the range values.
Is there a way to do this in the SHELL - I'm not interested in some of the driver products.