Multiple chained deferred functions using q in AngularJS stop returning data
Excerpt taken from the official doc on $q:
then(successCallback, errorCallback) – regardless of when the promise was or will be resolved or rejected calls one of the success or error callbacks asynchronously as soon as the result is available. The callbacks are called with a single argument the result or rejection reason.
This method returns a new promise which is resolved or rejected via the return value of the successCallback or errorCallback.
And for the return value of the successCallack or errorCallback, according to Domenic's slides:
if the return value is a promise then the promise adopts the returned promise's state otherwise the success callback is immediately called with the return value
Based on the definition, your code is missing the return
keyword. It should be as following:
asyncFn1(1)
.then(function(data){return asyncFn2(data)})
.then(function(data){return asyncFn2(data)})
.then(function(data){return asyncFn2(data)});
BoxerBucks
I really, really like code. I mean.. I really like it. I don't know why, but ever since I was a young lad... coding, designing, hacking, whatever. I've been a professional developer for a while now.. everything from .NET to Grails to Javascript. I'm currently in love with Javascript, Node, React and developing enterprise wide tools and libraries.
Updated on October 21, 2020Comments
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BoxerBucks over 3 years
I am trying to chain together multiple deferred function calls such that the next call gets the results of the previous deferred.resolve. When I chain together more than 2 of these calls, the data stops being returned.
Here is the basic code inside an angular controller:
$scope.runAsync = function() { var asyncFn1 = function(data){ var deferred = $q.defer(); $timeout(function(){ console.log("Async fn1 " + data); $scope.outputLines.push("Async fn1 " + data); deferred.resolve("Async fn1 " + data); },1000); return deferred.promise; } var asyncFn2 = function(data){ var deferred = $q.defer(); $timeout(function(){ console.log("Async fn2 " + data); $scope.outputLines.push("Async fn2 " + data); deferred.resolve("Async fn2 " + data); },1000); return deferred.promise; } asyncFn1(1) .then(function(data){asyncFn2(data)}) .then(function(data){asyncFn2(data)}) .then(function(data){asyncFn2(data)}); }
When I run this I get the following output:
Async fn1 1 Async fn2 Async fn1 1 Async fn2 undefined Async fn2 undefined
How can I chain them together so that the third call gets the result from the second call and the fourth gets the result from the third?
I have created a jsFiddle: http://jsfiddle.net/rhDyL/