NASM Linux Assembly Printing Integers

10,191

Solution 1

This is adding, not storing:

add edx, ecx        ; stores ecx in edx

This copies ecx to eax and then overwrites it with 4:

mov eax, ecx        ; moves ecx to eax for writing
mov eax, 4          ; sys call for write

EDIT:

For a 'write' system call:

eax = 4
ebx = file descriptor (1 = screen)
ecx = address of string
edx = length of string

Solution 2

After reviewing the other two answers this is what I finally came up with.

sys_exit        equ     1
sys_write       equ     4
stdout          equ     1

section .bss
    outputBuffer    resb    4       

section .text
    global _start

_start:
    mov  ecx, 1                 ; Number 1
    add  ecx, 0x30              ; Add 30 hex for ascii
    mov  [outputBuffer], ecx    ; Save number in buffer
    mov  ecx, outputBuffer      ; Store address of outputBuffer in ecx

    mov  eax, sys_write         ; sys_write
    mov  ebx, stdout            ; to STDOUT
    mov  edx, 1                 ; length = one byte
    int  0x80                   ; Call the kernel

    mov eax, sys_exit           ; system exit
    mov ebx, 0                  ; exit 0
    int 0x80                    ; call the kernel again

Solution 3

From man 2 write

ssize_t write(int fd, const void *buf, size_t count);

In addition to the other errors that have been pointed out, write() takes a pointer to the data and a length, not an actual byte itself in a register as you are trying to provide.

So you will have to store your data from a register to memory and use that address (or if it's constant as it currently is, don't load the data into a register but load its address instead).

Share:
10,191
finfet
Author by

finfet

Updated on June 28, 2022

Comments

  • finfet
    finfet almost 2 years

    I am trying to print a single digit integer in nasm assembly on linux. What I currently have compiles fine, but nothing is being written to the screen. Can anyone explain to me what I am doing wrong here?

    section .text
        global _start
    
    _start:
        mov ecx, 1          ; stores 1 in rcx
        add edx, ecx        ; stores ecx in edx
        add edx, 30h        ; gets the ascii value in edx
        mov ecx, edx        ; ascii value is now in ecx
        jmp write           ; jumps to write
    
    
    write:
        mov eax, ecx        ; moves ecx to eax for writing
        mov eax, 4          ; sys call for write
        mov ebx, 1          ; stdout
    
        int 80h             ; call kernel
        mov eax,1           ; system exit
        mov ebx,0           ; exit 0
        int 80h             ; call the kernel again 
    
  • finfet
    finfet over 12 years
    I tried this, and it also compiles fine, but nothing is being written to the screen.
  • finfet
    finfet over 12 years
    I still can't get it working, but I will make this the accepted answer.
  • Chris Stratton
    Chris Stratton over 12 years
    @FrozenWasteland - The remaining problem is mentioned in this answer, but without calling your attention specifically to it: "ecx = address of string edx = length of string" but you have been trying to provide the data byte itself inc ecx rather than the address there and a length in edx.
  • Chris Stratton
    Chris Stratton over 9 years
    Fortunately it was not the key part of thr answer, but included only as a convenience.