new line in Random Access File in java

Question

Whenever using the 'writeBytes' method of RandomAccessFile in java,it writes the text in the same line in the file. How can I get to a new line with RandomAccessFile only? (No BufferedReader).

Solution 1

Try this:

 RandomAccessFile file = new RandomAccessFile("e:\\demo.txt","rw");
 String originalString = "First line \nSeconf line \n";
 String updatedString = originalString.replace("\n","\r\n");
 file.writeBytes(updatedString);

Solution 2

You can write a line separator. In order to get the correct line separator for the currently running operating system, you'll have to look for the line.separator property. Something along these lines:

randomAccessFile.writeBytes(System.getProperty("line.separator"));

Comments

[sudmong]

that is what javadoc says "The write starts at the current position of the file pointer". try writing new line character before writing data.

[aceBox]

Basically using '\r\n' escape sequence worked with it.Thanks a lot,friend!!

[tom_mai78101]

Your method is wrong. write() does not take in String. You should probably change it to writeChars(). Another way is randomAccessFile.writeBytes(System.getProperty("line.separat‌​or"));, since writeBytes() can take in String as a parameter.

[Marc Baumbach]

@tom_mai78101 Thanks, fixed it.