Octave: find the minimum value in a row, and also it's index

Question

How would one find the minimum value in each row, and also the index of the minimum value?

octave:1> a = [1 2 3; 9 8 7; 5 4 6]
a =

   1   2   3
   9   8   7
   5   4   6

Solution 1

This is hard to find in the documentation. https://www.gnu.org/software/octave/doc/v4.0.3/Utility-Functions.html

octave:2> [minval, idx] = min(a, [], 2)
minval =

   1
   7
   4

idx =

   1
   3
   2

Solution 2

If A is your matrix, do:

[colMin, row] = min(A);
[rowMin, col] = min(A');

colMin will be the minimum values in each row, and col the column indexes. rowMin will be the minimum values in each column, and row the row indexes.

To find the index of the smallest element:

[colMin, colIndex] = min(min(A)); 
[minValue, rowIndex] = min(A(:,colIndex))

Solution 3

Suppose X is a matrix
row, col = Row and Column index of minimum value

[min_value, column_index] = min(X(:))
[row, col] = ind2sub(size(X),column_index)

Comments

[Ash]

hum.... If you type >help min in octave... You see Built-in Function: min (X, [], DIM) and also a long, detailed explanation that explains what you want. So, not hard to find :p

[beaker]

Not to mention doc min. A Google search on octave min also took me right to the link you posted.

[AG1]

IMHO, the documentation for Octave needs more examples for larger matrices with >1 dimension, the example in the documentation is for one row vector.