open a url on click of ok button in android

Question

I have to open a URL on Click of OK Button in a view. Can someone tell how to do this?

Solution 1

On Button click event write this:

Uri uri = Uri.parse("http://www.google.com"); // missing 'http://' will cause crashed
Intent intent = new Intent(Intent.ACTION_VIEW, uri);
startActivity(intent);

that open the your URL.

Solution 2

    Button imageLogo = (Button)findViewById(R.id.iv_logo);
    imageLogo.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            String url = "http://www.gobloggerslive.com";

            Intent i = new Intent(Intent.ACTION_VIEW);
            i.setData(Uri.parse(url));
            startActivity(i);
        }
    });

Solution 3

You can use the below method, which will take your target URL as the only input (Don't forget http://)

void GoToURL(String url){
    Uri uri = Uri.parse(url);
    Intent intent= new Intent(Intent.ACTION_VIEW,uri);
    startActivity(intent);
}

Solution 4

String url = "https://www.murait.com/";
if (url.startsWith("https://") || url.startsWith("http://")) {
    Uri uri = Uri.parse(url);
    Intent intent = new Intent(Intent.ACTION_VIEW, uri);
    startActivity(intent);
}else{
    Toast.makeText(mContext, "Invalid Url", Toast.LENGTH_SHORT).show();
}

You have to check that the URL is valid or not. If URL is invalid application may crash so that you have to check URL is valid or not by this method.

Solution 5

create an intent and set an action for it while passing the url to the intent

yourbtn.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                String theurl = "http://google.com";
                Uri urlstr = Uri.parse(theurl);
                Intent urlintent = new Intent();
                urlintent.setData(urlstr);
                urlintent.setAction(Intent.ACTION_VIEW);
                startActivity(urlintent);

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Comments

[Harry Joy]

Use HttpUrlConnection.

[Tushar]

public void openWebURL( String inURL ) { Intent browse = new Intent( Intent.ACTION_VIEW , Uri.parse( inURL ) ); startActivity( browse ); }

[Ganapathy C]

This will work perfectly dude.. so 1 up...

[Harry Joy]

@tushar: have you tried it? i think it should work properly. do you get any error while running this code?

[Givantha Kalansuriya]

try this way vogella.de/articles/AndroidIntent/article.html

[Chris - Jr]

OR startActivity(new Intent(Intent.ACTION_VIEW,Uri.parse("http://www.google.com")‌​)

[Muhammad Noman]

@Chris-Jr you have missed the last parenthesis i.e. )

[Ian]

How is this different from opening a webview item?

[Tugay]

Can you please give some explanation?