Oracle 11g "Bind variable does not exist"

24,213

Form the string like this below.

t.column_name || ' Like ''%''||:1||''%'''

Bind variable should not be included within single quotes, as it would be treated as a String literal instead. So when you used USING it ended up with this excpetion.

Share:
24,213
bassman592
Author by

bassman592

Updated on July 09, 2022

Comments

  • bassman592
    bassman592 almost 2 years

    I am getting an "ORA01006 Bind variable does not exist at line 15 "error in the following code:

    DECLARE
      v_search_string varchar2(4000) := 'OK';
      v_query_str VARCHAR2(4000);
      match_count integer;
    BEGIN  
      FOR t IN (SELECT owner,
                       table_name, 
                       column_name 
                  FROM all_tab_columns
                 WHERE data_type in ('CHAR', 'VARCHAR2', 'NCHAR', 'NVARCHAR2') And TABLE_NAME = 'T1' And OWNER = 'O1') 
      LOOP   
        Begin
          v_query_str := 'SELECT COUNT(*) FROM '|| t.table_name || ' WHERE ' || t.column_name || ' Like ''' || '%:1%' || '''';
          dbms_output.put_line(v_query_str);
          EXECUTE Immediate v_query_str
          INTO match_count  
          USING v_search_string; 
          IF match_count >= 0 THEN 
            dbms_output.put_line( t.owner || '.' || t.table_name ||' '||t.column_name||' '||match_count );
          END IF; 
        END;
      END LOOP;
    END;
    

    I'm just trying to loop through all the character columns in the table and count how many values in each match the v_search_string value.

    The line "dbms_output.put_line(v_query_str);" prints one line: SELECT COUNT(*) FROM T1 WHERE Col1 Like '%:1%'

    There are 10 columns in the table that are the specified types.

    There is obviously a bind variable there (%1), so I can't figure out what's going on.