PHP and MySQL: Order by most recent date and limit 10

67,917

Solution 1

This should do it :

$result = mysql_query("SELECT * FROM notes WHERE note_author_id='$u_id' ORDER BY date_time DESC LIMIT 0, 10");

Solution 2

use:

SELECT * FROM notes WHERE note_author_id='$u_id' ORDER BY date_time DESC LIMIT 10

DESC : descending order ( from newest to oldest ) LIMIT 10: first 10 records found.

Solution 3

Try

$result = mysql_query("SELECT * FROM notes WHERE note_author_id='$u_id' ORDER BY date_time DESC LIMIT 10");

For a more detailed explanation on ORDER and LIMIT, visit the MySQL doc's articles about sorting rows and the basic select syntax (look for a bullet describing LIMIT).

Solution 4

give like

 ORDER BY date_time DESC

otherwise you are sorting them in ascending order.. thats why older ones come first

Solution 5

Do this

$result = mysql_query("SELECT * FROM notes WHERE note_author_id='$u_id' ORDER BY date_time DESC LIMIT 0, 10");
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James
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James

Updated on January 24, 2020

Comments

  • James
    James over 4 years

    I am building a notes system on my site and I've got to the stage where users can post notes into the MySQL database using PHP and then PHP prints them out on a page. However, when they print/echo out, the oldest one appears first but I want the most recent first. I also want them to be limited to 10, so only 10 appear on the page. Here is my PHP code, your help will be much appreciated:

    // initialize some variables
    $notedisplaylist = "";
    $myObject = "";
    $result = mysql_query("SELECT * FROM notes WHERE note_author_id='$u_id' ORDER BY         date_time");
    
    while($row = mysql_fetch_array($result)){
      $note_title = $row["note_title"];
      $note_body = $row["note_body"];
      $date = $row["date_time"];
      $notedisplaylist .= '<h2>' . $note_title . '</h2><br /><p>' . $note_body . '</p><hr /><p>Noted: ' . $date . '</p><hr /><br />';
    }