php compare/diff an array with an array of objects
Solution 1
Assuming $objects
is your array of objects, and $values
is your array of values to remove...
You could use a foreach
loop if you want to return objects:
$values = array(5, 6);
$objects = array(
(object) array("id" => 1),
(object) array("id" => 3),
(object) array("id" => 5),
(object) array("id" => 6),
(object) array("id" => 7)
);
foreach($objects as $key => $object) {
if(in_array($object->id,$values)) {
unset($objects[$key]);
}
}
Live demo (0.008 sec)
If you want to use the diff
function itself (that's possible but awkward, less readable and will just return an array of values) you can (as Baba suggested) return the id
of the object inline:
$values = array(5, 6);
$objects = array(
(object) array("id" => 1),
(object) array("id" => 3),
(object) array("id" => 5),
(object) array("id" => 6),
(object) array("id" => 7)
);
$diff = array_diff(array_map(function ($object) {
return $object->id;
}, $objects), $values);
Live demo (0.008 sec)
Solution 2
You can try :
$diff = array_diff(array_map(function ($v) {
return $v->id;
}, $array2), $array1);
Solution 3
Loop over the second array and use in_array
method to check for existing values in first
$firstArray = array(5, 6);
foreach ($objects as $key => $object) {
if (in_array($object->id, $firstArray)) {
unset($objects[$key];
}
}
Solution 4
For versions older than 5.3
foreach( $arr_2nd as $key => $val )
{
$arr_2nd[$key] = $val->id;
}
array_diff( $arr_1st, $arr_2nd );
Comments
-
feub almost 2 years
I have 2 PHP arrays, a simple one:
array 0 => int 5 1 => int 6
and an array of objects:
array 0 => object(stdClass)[43] public 'id' => int 1 1 => object(stdClass)[46] public 'id' => int 3 2 => object(stdClass)[43] public 'id' => int 5 3 => object(stdClass)[46] public 'id' => int 6 4 => object(stdClass)[46] public 'id' => int 7
I'd like to make a diff of these 2 arrays to eliminate in the second those present in the first. In this example, i don't want the ids 5 and 6 in the second array. But i need help ;>
Thank you.
fabien