PHP echo inside echo

33,123

Solution 1

That is some of the ugliest code I have ever seen...

<?php 
echo '
<h3>Hello</h3>';

while ($row_indiosct = mysql_fetch_assoc($indiosct))
{
  echo '
    <div class="indios">
      <a href="indio.php?id='.$row_indiosct['id'].'">
        <img src="galeria/indios/'. $row_indiosct['foto'].'" alt="'.$row_indiosct['nome'].'" />
      <br />'.$row_indiosct['nome'].'</a>
    </div>';
} 
?>

You could also use the HEREDOC syntax.

Solution 2

Don't do this. Multi-line echoes, especially when you've got embedded quotes, quickly become a pain. Use a HEREDOC instead.

<?php 

echo <<<EOL
<h3>Hello</h3>
...
<div class"indios">
...
EOL;

and yes, the PHP inside your echo will NOT execute. PHP is not a "recursively executable" language. If you're outputting a string, any php code embedded in that string is not executed - it'll be treated as part of the output, e.g.

echo "<?php echo 'foo' ?>"

is NOT going to output just foo. You'll actually get as output

<?php echo 'foo' ?>
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33,123
André Ferreira
Author by

André Ferreira

Updated on April 05, 2020

Comments

  • André Ferreira
    André Ferreira about 4 years

    I'm trying to call an HTML/PHP content that it's inside my database using:

    <?php echo $row_content['conteudo']; ?>
    

    When the row is called the HTML appears correctly but the PHP doesn't. I belieave it's cause of the echo inside the main echo.

    <?php echo "
    <h3>Hello</h3>
    <?php do { ?>
      <div class=\"indios\">
        <a href=\"indio.php?id=<?php echo $row_indiosct['id']; ?>\">
          <img src=\"galeria/indios/<?php echo $row_indiosct['foto']; ?>\" alt=\"<?php echo $row_indiosct['nome']; ?>\" />
          <br /><?php echo $row_indiosct['nome']; ?></a></div>
      <?php } while ($row_indiosct = mysql_fetch_assoc($indiosct)); ?> "
     ?>
    

    The line one of this code is the same echo as the first code field, it's not repeating, it's there just for help and to understand where is the problem.

    I already fixed some quotation marks but it gives an error in the line of the 1st echo.

  • Sjors Hijgenaar
    Sjors Hijgenaar over 3 years
    This is awesome! Thanks a bunch