PHP: How to check if a date is today, yesterday or tomorrow

Question

I would like to check, if a date is today, tomorrow, yesterday or else. But my code doesn't work.

Code:

$timestamp = "2014.09.02T13:34";
$date = date("d.m.Y H:i");
$match_date = date('d.m.Y H:i', strtotime($timestamp));

if($date == $match_date) { 

    //Today

} elseif(strtotime("-1 day", $date) == $match_date) {

    //Yesterday

} elseif(strtotime("+1 day", $date) == $match_date) {

    //Tomorrow

} else {

    //Sometime

}

The Code always goes in the else case.

Solution 1

First. You have mistake in using function strtotime see PHP documentation

int strtotime ( string $time [, int $now = time() ] )

You need modify your code to pass integer timestamp into this function.

Second. You use format d.m.Y H:i that includes time part. If you wish to compare only dates, you must remove time part, e.g. `$date = date("d.m.Y");``

Third. I am not sure if it works in the same way for you, but my PHP doesn't understand date format from $timestamp and returns 01.01.1970 02:00 into $match_date

$timestamp = "2014.09.02T13:34";
date('d.m.Y H:i', strtotime($timestamp)) === "01.01.1970 02:00";

You need to check if strtotime($timestamp) returns correct date string. If no, you need to specify format which is used in $timestamp variable. You can do this using one of functions date_parse_from_format or DateTime::createFromFormat

This is a work example:

$timestamp = "2014.09.02T13:34";

$today = new DateTime("today"); // This object represents current date/time with time set to midnight

$match_date = DateTime::createFromFormat( "Y.m.d\\TH:i", $timestamp );
$match_date->setTime( 0, 0, 0 ); // set time part to midnight, in order to prevent partial comparison

$diff = $today->diff( $match_date );
$diffDays = (integer)$diff->format( "%R%a" ); // Extract days count in interval

switch( $diffDays ) {
    case 0:
        echo "//Today";
        break;
    case -1:
        echo "//Yesterday";
        break;
    case +1:
        echo "//Tomorrow";
        break;
    default:
        echo "//Sometime";
}

Solution 2

<?php 
 $current = strtotime(date("Y-m-d"));
 $date    = strtotime("2014-09-05");

 $datediff = $date - $current;
 $difference = floor($datediff/(60*60*24));
 if($difference==0)
 {
    echo 'today';
 }
 else if($difference > 1)
 {
    echo 'Future Date';
 }
 else if($difference > 0)
 {
    echo 'tomorrow';
 }
 else if($difference < -1)
 {
    echo 'Long Back';
 }
 else
 {
    echo 'yesterday';
 }  
?>

Solution 3

function getRangeDateString($timestamp) {
    if ($timestamp) {
        $currentTime=strtotime('today');
        // Reset time to 00:00:00
        $timestamp=strtotime(date('Y-m-d 00:00:00',$timestamp));
        $days=round(($timestamp-$currentTime)/86400);
        switch($days) {
            case '0';
                return 'Today';
                break;
            case '-1';
                return 'Yesterday';
                break;
            case '-2';
                return 'Day before yesterday';
                break;
            case '1';
                return 'Tomorrow';
                break;
            case '2';
                return 'Day after tomorrow';
                break;
            default:
                if ($days > 0) {
                    return 'In '.$days.' days';
                } else {
                    return ($days*-1).' days ago';
                }
                break;
        }
    }
}

Solution 4

Simple one liners for today/yesterday/tomorrow:

$someDate = '2021-11-07'; // date in any format

$isToday = date('Ymd') == date('Ymd', strtotime($someDate));
$isYesterday = date('Ymd') == date('Ymd', strtotime($someDate) + 86400);
$isTomorrow = date('Ymd') == date('Ymd', strtotime($someDate) - 86400);

Solution 5

Pass the date into the function.

            <?php
                function getTheDay($date)
                {
                    $curr_date=strtotime(date("Y-m-d H:i:s"));
                    $the_date=strtotime($date);
                    $diff=floor(($curr_date-$the_date)/(60*60*24));
                    switch($diff)
                    {
                        case 0:
                            return "Today";
                            break;
                        case 1:
                            return "Yesterday";
                            break;
                        default:
                            return $diff." Days ago";
                    }
                }
            ?>

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