php insert value into array of arrays using foreach
foreach
works with a copy of $item
, so you cannot modify your original array inside the foreach
. One way to work around this is to use the &
operator.
foreach($array as &$item) {
if (is_array($item)) {
$item['key3'] = 'val3';
}
}
Another, more elegant way would be to use array_walk()
:
array_walk($array, function (&$v, $k) {
if (is_array($v)) {
$v['key3'] = 'val3';
}
});
This example will work from PHP 5.3, where Closures were introduced.
Benjamin Thvedt
I prefer to keep an air of mystery about myself
Updated on January 29, 2020Comments
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Benjamin Thvedt over 4 years
I have a pretty basic question but I am stuck. I am pretty new to php and I have an array like this:
$array = array( 'one' => 1, 'two' => array('key1' => 'val1','key2' => 'val2'), 'three' => array('key1' => 'val1','key2' => 'val2'), 'four' => array('key1' => 'val1','key2' => 'val2') );
and for each of the arrays in the array (that is, 'two, 'three', and 'four'), I want to insert 'key3' => 'val3' into those arrays.
I tried this:
foreach($array as $item) { if (gettype($item) == "array") { $item['key3'] = 'val3'; } }
But it doesn't work, and I'm not sure why. Using various print_r's all over the place, it seems to insert 'key3' => 'val3' into $item if I print it out in the loop, but the original array seems unchanged. I also tried a regular for loop but that didn't work either.
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moskito-x almost 11 years$item is only generated for the loop . You mean
&$array['key3'] = 'val3';
! -
kapa almost 11 years@moskito-x I certainly mean what I wrote. That's the point of it. Check the
foreach
manual page I linked. -
moskito-x almost 11 yearsTo change $item is useless. Will be always overwritten by the next loop.
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moskito-x almost 11 yearsBut
As foreach relies on the internal array pointer changing it within the loop may lead to unexpected behavior.
therefore you have to unset the reference .unset($item);
// break the reference with the last element. structures.foreach -
Benjamin Thvedt almost 11 yearsThanks for the great answer. The first solution worked fine but the second solution didn't seem to work, it's obvious I need to get a little better at php. Can I just stick that & symbol anywhere? Wow that would change things. Also, thanks for the tip on using unset($item), not knowing that would have eventually sunk me somewhere down the line for sure!
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kapa almost 11 years@BenjaminThvedt Fixed the second one. Don't overuse the
&
operator, most of the time there is a better solution. -
Mark Carpenter Jr almost 7 yearsWhile not the answer to the question, this helped me better understand the relationship between the
$key
word and the$item
.