PHP - making a switch statement using id from form input

Question

I'm making a short quiz in PHP that tells you what creature your thinking of based on 4 yes/no questions. I have made it so that depending on your answer to each question you get taken to a different question, I did this using mainly switch statements.

My question is is there any way that I can make a switch statement with the condition as the id from the submit buttons from the form?

      echo "<form method ='post' action='Creatures.php'>
     <input type='submit' name='answer' id='1' value='Yes' />
     <input type='submit' name='answer' id='2' value='No' />
     </form>";

This is the form I'm using to display the buttons, I have made it so that each button has a different id so at the end of the quiz, depending on what the id of the last button pressed is, I can display the right answer. Below is what I tried to do but it didn't work.

switch($_POST['id'])
{
 case 1: echo "It's a goldfish";
 case 2: echo "It's a eel";
}

Also these fields are the only ones which use id's throughout the whole web page, any suggestions on how I can get this to work properly, not necessarily using switch statements?

Solution 1

switch($_POST['answer']) {

case 'Yes':
   // do soemthing
   break;
case 'No':
   // do something
   break;
}

Solution 2

There are many errors to this. Please study the following:

echo '<form method ="post" action="Creatures.php">
<button name="answer" type="submit" value="Yes">Yes</button>
<button name="answer" type="submit" value="No">No</button>
</form>';

switch($_POST['answer'])
{
   case 'Yes':
        echo "It's a goldfish";
        break;
   case 'No':
        echo "It's a eel";
        break;
}

Also see this and this.

Comments

[tigrang]

and switch 'Yes' and 'No' - see my comment

[Waqar Alamgir]

as you have same name='answer' they can not be of 2 at the same time unless you define them as array like name='answer[]'

[tigrang]

But only 1 is ever being posted. They are submit buttons.

[Harry12345]

I have done everything you said and have added a hidden input field, so it is now working, yaayyy!