Php-MySql Query , Selecting Data According to DateTime

Question

I would like to get number of rows that have same date. But one second must be negligible.

For example ; 2012-01-03 13:12:28 and 2012-01-03 13:12:27 should be perceived as the same.

( I have a table name is myTable and the datetime column name is date )

I hope you will help me..

Solution

It's as simple as:

SELECT * FROM myTable WHERE date >= '2012-01-03 13:12:27' AND date <= '2012-01-03 13:12:28';

If you want to build it up from a variable, you could do this:

$date = '2012-01-03 13:12:27';
$timestamp = strtotime($date);
$mysqli = new mysqli();

// Note: allowing 1 second either side, this is up to you
$lower = date('Y-m-d H:i:s', $timestamp - 1);
$upper = date('Y-m-d H:i:s', $timestamp + 1);

$stmt = $mysqli->prepare('SELECT * FROM myTable WHERE date >= ? AND date <= ?');
$stmt->bind_param('ss', $lower, $upper);
$stmt->execute();

EDIT: As per your comment below, the following SQL should return what you're after. Note that if a date contains '2012-01-03 13:12:28' it will be counted for both :27 and :28.

SELECT
    upper_date,
    COALESCE(lower_count, 0) + upper_count
FROM
    (SELECT
        date AS upper_date,
        COUNT(1) AS upper_count
    FROM myTable
    GROUP BY date
    ) AS upper
LEFT JOIN
    (SELECT
        date - INTERVAL 1 SECOND AS lower_date,
        COUNT(1) AS lower_count
    FROM myTable
    GROUP BY date
    ) AS lower
ON upper.upper_date = lower.lower_date