Pivot table strings grouping under pivot column?

Question

JOB        ENAME
--------  ----------
ANALYST    SCOTT
ANALYST    FORD
CLERK      SMITH
CLERK      ADAMS
CLERK      MILLER
CLERK      JAMES
MANAGER    JONES
MANAGER    CLARK
MANAGER    BLAKE
PRESIDENT  KING
SALESMAN   ALLEN
SALESMAN   MARTIN
SALESMAN   TURNER
SALESMAN   WARD

I would like to format the result set such that each job gets its own column:

CLERKS  ANALYSTS  MGRS   PREZ  SALES
------  --------  -----  ----  ------
MILLER  FORD      CLARK  KING  TURNER
JAMES   SCOTT     BLAKE        MARTIN
ADAMS             JONES        WARD
SMITH 

I tried

SELECT ANALYST, CLERK, MANAGER, PRESIDENT, SALESMAN from
(
  SELECT ename, job from emp
) as st
pivot
(
  SELECT ename
  FOR job in (ANALYST, CLERK, MANAGER, PRESIDENT, SALESMAN)
) as pivottable

I'm getting these errors

Msg 156, Level 15, State 1, Line 7
Incorrect syntax near the keyword 'SELECT'.
Msg 156, Level 15, State 1, Line 8
Incorrect syntax near the keyword 'in'.

How to use pivot to group strings under pivot column?

Solution

When you are using the PIVOT function, you are required to use an aggregate function. The syntax of a PIVOT is:

From MSDN:

SELECT <non-pivoted column>,
    [first pivoted column] AS <column name>,
    [second pivoted column] AS <column name>,
    [last pivoted column] AS <column name>
FROM
    (<SELECT query that produces the data>)
    AS <alias for the source query>
PIVOT
(
    <aggregation function>(<column being aggregated>)
FOR
[<column that contains the values that will become column headers>]
    IN ( [first pivoted column], [second pivoted column],
    ... [last pivoted column])
) AS <alias for the pivot table>
<optional ORDER BY clause>;

With a string, you will need to use either the MIN() or MAX() aggregate function. The problem that you will run into is that these functions will return only one value for each column.

So in order to get the PIVOT to work, you will need to provide a distinct value that will keep the rows separate during the GROUP BY.

For your example, you can use row_number():

SELECT ANALYST, CLERK, MANAGER, PRESIDENT, SALESMAN 
from
(
  SELECT ename, job,
    row_number() over(partition by job order by ename) rn
  from emp
) as st
pivot
(
  max(ename)
  FOR job in (ANALYST, CLERK, MANAGER, PRESIDENT, SALESMAN)
) as pivottable

See SQL Fiddle with Demo.

The row_number() creates a distinct value that is assigned to each row in the job, when you apply the aggregate function and the GROUP BY in the PIVOT you will still get separate rows.

Comments

[Shaibal Ahmed]

What a wonderful solution. Thank you so much Taryn.