$.post fails with error "...is not a function"
Solution 1
Your syntax is broken. What you're attempting to do is call the .success property of the $.post() method, which obviously doesnt exist. It looks like you also need to be using the $.ajax
method instead of $.post
:
$.ajax({
type: 'POST',
url: 'mypage.php',
data: { url: pageurl },
beforeSend: function()
{
alert('Fetching....');
},
success: function()
{
alert('Fetch Complete');
},
error: function()
{
alert('Error');
},
complete: function()
{
alert('Complete')
}
});
Solution 2
That syntax is only supported in jQuery 1.5+ (with the introduction of deferreds). It sounds like you're using a earlier version of jQuery. If you aren't able to upgrade, pass the success/error/complete handlers as methods of the options object (like in Tejs's example).
Solution 3
The jqxhr object is chainable from v1.5. Make sure you have this version or later.
Ref: jQuery 1.5 released, now with Deferred Objects
Lazloman
Updated on June 29, 2022Comments
-
Lazloman almost 2 years
Here is my code:
var jqxhr = $.post("mypage.php", {url:pageurl}, function() { alert("fetching..."); }) .success(function() { alert("fetch complete!"); }) .error(function() { alert("error!"); }) .complete(function() { alert("complete"); }); // Set another completion function for the request above jqxhr.complete(function(){ alert("second complete"); });
I get the alert("Fetching...") dialog box, but the rest of the code does not complete. I get the error: Error: $.post("sec_fetch_report.php", function () {alert("fetching...");}).success is not a function
I thought maybe I might be missing the jquery libs, but I have another function that calls $.post and it runs just fine. Is there a syntax error I'm missing somewhere or what? Thanks