Print full path of files and sizes with find in Linux

Question

If there was only a one-level menu tree, activating and deactivating links would not be a problem.

<ul class="sidemenu">
 <li class="active"><a href="#">some title</a></li>
 <li><a href="#">some title</a></li>
 <li><a href="#">some title</a></li>
 etc ...
</ul>

$('.sidemenu').on('click', 'li', function() {
    $('.sidemenu li.active').removeClass('active');
    $(this).addClass('active');
});

I needed to solve the activation / deactivation of each link in the two-level menu tree, but I did not find the correct or working solution. I understand very well that this jquery code is suitable for a one-level menu.

I was looking everywhere for some good clues. My head is empty.

My jsfiddle code is here: https://jsfiddle.net/kukrik/d3pcrhnm/15/.

I would be very grateful if anyone has good advice or experiences to share.

Solution 1

Instead of -exec ls -lh {} \; you can also use the printf option:

find / \( -path /proc -o -path /sys \) -prune -o -newer /tmp/test -printf "%s %p\n" | less

Although that will just print the size in bytes and not in the nice human-readable format ls supports.

Solution 2

Add -d to the ls command.

find / \( -path /proc -o -path /sys \) -prune -o -newer /tmp/test -exec ls -lhd {} \; | less

That will also fix the problem you were bound to have with files showing up twice in your list.

Comments

[l0b0]

+1 for POSIX and non-ls solution.

[vonbrand]

The day you need to use some other system or user, it will bite you.

[Tiit Papp]

Many thanks to Çağrı! Often a seemingly big problem turns out to be very simple. I once thought about this possible solution. It was this Css code that blocked my normal thinking. Here is a working example: jsfiddle.net/kukrik/gzodabnm/11