Print specific words/numbers via grep/cut commands

Question

I have a file test.txt, which contains the following result:

service_name1= apple/ball/cat/dog/egg/12.34.56/ball/apple
service_name2= fan/girl/house/ice/joker/23.45.67/fan/girl

and so on up to service_name1500

I want output like :

egg 12.34.56
joker 23.45.67

and so on: the version number along with the word before that.

Solution 1

This should be a simple cut job:

cut -d/ -f5,6 --output-delimiter=" "

• -d/ sets the input delimiter as /
• -f5,6 outputs only the 5th and 6th field
• --output-delimiter=" " sets the output delimiter as a space

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Same thing with awk, awk by default sets the output field separator as space:

awk -F/ '{print $5,$6}'

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Example:

% cat file.txt
service_name1= apple/ball/cat/dog/egg/12.34.56/ball/apple
service_name2= fan/girl/house/ice/joker/23.45.67/fan/girl

% cut -d/ -f5,6 --output-delimiter=" " file.txt
egg 12.34.56
joker 23.45.67

% awk -F/ '{print $5,$6}' file.txt
egg 12.34.56 
joker 23.45.67

Solution 2

a sed solution (works whether the field position of the version string is consistent or not, but the form of the version string must be consistent)

$ sed -r 's#.*/(.*)/([0-9]{2}\.[0-9]{2}\.[0-9]{2}).*#\1 \2#' test.txt
egg 12.34.56

joker 23.45.67

Explanation

• -r use ERE so we don't have to escape () metacharacters
• s#old#new# find pattern old and replace with new
• .* match any or no characters in this position
• (stuff) remember stuff for later
• [0-9]{2}\.[0-9]{2}\.[0-9]{2} a pattern of [2 digits].[2 digits].[2 digits]
• \1 \2 the two remembered patterns with a space in between

Solution 3

This will do it:

cut -d'/' -f5-6 test.txt | tr -s "/" " "

Solution 4

If you deal with fixed word positions this would work:

grep -e 'service_name[0-9]*=' test.txt|awk -F'/' '{ print $5" "$6 }'

Solution 5

$sed -r 's/.*\/([[:alpha:]]+)\/([\.0-9]*)\/.*/\1 \2/' test.txt

Explanation:

• .* at the beginning and end cuts all characters that do not match the following
• ([[:alpha:]]+) first subgroup in brackets matches only alphabetical characters
• \/ matches a slash which will be cut out
• next subgroup ([\.0-9]*) matches numbers and points and stores it in the second register
• after the single slash / comes the substitution with \1 \2 inserts the first and second register from the matched subgroups

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Comments

[SeDav]

is it necessary to do it with grep? I'd use sed or awk