Print without space in python 3

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Solution 1

You can use the sep parameter to get rid of the spaces:

>>> print("a","b","c")
a b c
>>> print("a","b","c",sep="")
abc

I don't know what you mean by "Java style"; in Python you can't add strings to (say) integers that way, although if a and b are strings it'll work. You have several other options, of course:

>>> print("a = ", a, ", b = ", b, sep="") 
a = 2, b = 3
>>> print("a = " + str(a) + ", b = " + str(b))
a = 2, b = 3
>>> print("a = {}, b = {}".format(a,b))
a = 2, b = 3
>>> print(f"a = {a}, b = {b}")
a = 2, b = 3

The last one requires Python 3.6 or later. For earlier versions, you can simulate the same effect (although I don't recommend this in general, it comes in handy sometimes and there's no point pretending otherwise):

>>> print("a = {a}, b = {b}".format(**locals()))
a = 2, b = 3
>>> print("b = {b}, a = {a}".format(**locals()))
b = 3, a = 2

Solution 2

The actual syntax of the print() function is

print(*objects, sep=' ', end='\n', file=sys.stdout, flush=False)

You can see it has an arg sep with default value ' '. That's why space gets inserted in between.

print("United","States")            #Output: United States
print("United","States",sep="")     #Output: UnitedStates

Solution 3

You can also use

print("%d%d" %(a,b))

to print a and b not seperated by spaces in form of a formatted string. This is similar to the one in c.

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H.v.M.
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Updated on November 28, 2020

Comments

  • H.v.M.
    H.v.M. over 3 years

    I'm new to Python, and I'm wondering how to print multiple values without having the extra space added in between. I want the output ab rather than a b without having to call print twice:

    print("a", end="")
    print("b")
    

    Also, I have the following code:

    a = 42
    b = 84 
    

    and I want to print their values as a = 42, b = 84, yet if I do

    print("a = ", a, ", ", b = ", b)
    

    extra spaces are added (it outputs a = 42 , b = 84)

    Whereas the Java style,

    print("a = " + a + ", b = " + b)
    

    raises a TypeError.