prop('disabled', false); is not working

Question

I want to make a button that will be disable when checkbox is false. But prop('disabled', false); isn't working.

$(function() {
    $(this).click(function() {
        if ($('#аgree').prop(':checked')) {
            $('#button').prop('disabled', false);
        } else {
            $('#button').prop('disabled', true);
        }
    });
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p class="text-center">З правилами анкетування ознайомлений(а) і згоден(на) @Html.CheckBox("Agree", false, new { id = "agree" }) </p>
<p class="text-center"><input type="button" id="button" disabled="disabled" value="Пройти анкетування" onclick="location.href='@Url.Action("Form")'" /></p>

Solution 1

In your code, this refers to the DOM.

Change it to

$("#agree").change(function() {
    if ($(this).is(':checked')) {
        $('#button').prop('disabled', false);
    } else {
        $('#button').prop('disabled', true);
    }
});

Inside the event handler, this refers to the element that triggered the change event.

or simply:

$("#agree").click(function() {
    $('#button').prop('disabled', !$(this).is(':checked'));
});

Solution 2

You can try removing the attribute.

$('#button').removeAttr('disabled')

Comments

[Dmytro Petrenko]

$("#agree").click(function() { $('#button').prop('disabled', !$(this).is(':checked')); }); It`s right. Thank you

[Kewal Shah]

Thanks, I had the same problem as OP but this solution worked like a charm!