pyspark : NameError: name 'spark' is not defined

115,870

Solution 1

Since you are calling createDataFrame(), you need to do this:

df = sqlContext.createDataFrame(data, ["features"])

instead of this:

df = spark.createDataFrame(data, ["features"])

spark stands there as the sqlContext.


In general, some people have that as sc, so if that didn't work, you could try:

df = sc.createDataFrame(data, ["features"])

Solution 2

You can add

from pyspark.context import SparkContext
from pyspark.sql.session import SparkSession
sc = SparkContext('local')
spark = SparkSession(sc)

to the begining of your codes to define a SparkSession, then the spark.createDataFrame() should work.

Solution 3

Answer by 率怀一 is good and will work for the first time. But the second time you try it, it will throw the following exception :

ValueError: Cannot run multiple SparkContexts at once; existing SparkContext(app=pyspark-shell, master=local) created by __init__ at <ipython-input-3-786525f7559f>:10 

There are two ways to avoid it.

1) Using SparkContext.getOrCreate() instead of SparkContext():

from pyspark.context import SparkContext
from pyspark.sql.session import SparkSession
sc = SparkContext.getOrCreate()
spark = SparkSession(sc)

2) Using sc.stop() in the end, or before you start another SparkContext.

Solution 4

If it errors you regarding other open session do this:

from pyspark.context import SparkContext
from pyspark.sql.session import SparkSession
sc = SparkContext.getOrCreate();

spark = SparkSession(sc)
scraped_data=spark.read.json("/Users/reihaneh/Desktop/nov3_final_tst1/")

Solution 5

You have to import the spark as following if you are using python then it will create a spark session but remember it is an old method though it will work.

from pyspark.shell import spark
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Edamame
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Edamame

Updated on January 16, 2022

Comments

  • Edamame
    Edamame over 2 years

    I am copying the pyspark.ml example from the official document website: http://spark.apache.org/docs/latest/api/python/pyspark.ml.html#pyspark.ml.Transformer

    data = [(Vectors.dense([0.0, 0.0]),), (Vectors.dense([1.0, 1.0]),),(Vectors.dense([9.0, 8.0]),), (Vectors.dense([8.0, 9.0]),)]
    df = spark.createDataFrame(data, ["features"])
    kmeans = KMeans(k=2, seed=1)
    model = kmeans.fit(df)
    

    However, the example above wouldn't run and gave me the following errors:

    ---------------------------------------------------------------------------
    NameError                                 Traceback (most recent call last)
    <ipython-input-28-aaffcd1239c9> in <module>()
          1 from pyspark import *
          2 data = [(Vectors.dense([0.0, 0.0]),), (Vectors.dense([1.0, 1.0]),),(Vectors.dense([9.0, 8.0]),), (Vectors.dense([8.0, 9.0]),)]
    ----> 3 df = spark.createDataFrame(data, ["features"])
          4 kmeans = KMeans(k=2, seed=1)
          5 model = kmeans.fit(df)
    
    NameError: name 'spark' is not defined
    

    What additional configuration/variable needs to be set to get the example running?

    • Edamame
      Edamame over 7 years
      change to sqlContext works. thanks!
  • Edamame
    Edamame over 7 years
    If I use sc, it doesn't work. But if I use sqlContext, it works. Is this expected?
  • gsamaras
    gsamaras over 7 years
    Yes @Edamame, it all depends on how you import stuff.. :)