Python argparse command line flags without arguments
Solution 1
As you have it, the argument w
is expecting a value after -w
on the command line. If you are just looking to flip a switch by setting a variable True
or False
, have a look here (specifically store_true and store_false)
import argparse
parser = argparse.ArgumentParser()
parser.add_argument('-w', action='store_true')
where action='store_true'
implies default=False
.
Conversely, you could haveaction='store_false'
, which implies default=True
.
Solution 2
Adding a quick snippet to have it ready to execute:
Source: myparser.py
import argparse
parser = argparse.ArgumentParser(description="Flip a switch by setting a flag")
parser.add_argument('-w', action='store_true')
args = parser.parse_args()
print args.w
Usage:
python myparser.py -w
>> True
Solution 3
Your script is right. But by default is of None type. So it considers true of any other value other than None is assigned to args.argument_name variable.
I would suggest you to add a action="store_true". This would make the True/False type of flag. If used its True else False.
import argparse
parser = argparse.ArgumentParser('parser-name')
parser.add_argument("-f","--flag",action="store_true",help="just a flag argument")
usage
$ python3 script.py -f
After parsing when checked with args.f it returns true,
args = parser.parse_args()
print(args.f)
>>>true
interstar
I'm a programmer, teacher and digital artist. See http://sdi.thoughtstorms.info/ for most of my programming related thoughts.
Updated on August 01, 2022Comments
-
interstar almost 2 years
How do I add an optional flag to my command line args?
eg. so I can write
python myprog.py
or
python myprog.py -w
I tried
parser.add_argument('-w')
But I just get an error message saying
Usage [-w W] error: argument -w: expected one argument
which I take it means that it wants an argument value for the -w option. What's the way of just accepting a flag?
I'm finding http://docs.python.org/library/argparse.html rather opaque on this question.