Python pandas dataframe group by based on a condition

90,487

Solution 1

The grouped result is a regular DataFrame, so just filter the results as usual:

 import pandas as pd

 df = pd.DataFrame({'a': ['a', 'b', 'a', 'a', 'b', 'c', 'd']})
 after = df.groupby('a').size()
 >> after
 a
 a    3
 b    2
 c    1
 d    1
 dtype: int64

 >> after[after > 2]
 a
 a    3
 dtype: int64

Solution 2

Try this code:

df.groupby('column').filter(lambda group: group.size > X)
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ahajib
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ahajib

In God we trust, all others must bring data !

Updated on July 29, 2022

Comments

  • ahajib
    ahajib almost 2 years

    My question is simple, I have a dataframe and I groupby the results based on a column and get the size like this:

    df.groupby('column').size()
    

    Now the problem is that I only want the ones where size is greater than X. I am wondering if I can do it using a lambda function or anything similar? I have already tried this:

    df.groupby('column').size() > X
    

    and it prints out some True and False values.