Python: startswith any alpha character

Question

How can I use the startswith function to match any alpha character [a-zA-Z]. For example I would like to do this:

if line.startswith(ALPHA):
    Do Something

Solution 1

If you want to match non-ASCII letters as well, you can use str.isalpha:

if line and line[0].isalpha():

Solution 2

You can pass a tuple to startswiths() (in Python 2.5+) to match any of its elements:

import string
ALPHA = string.ascii_letters
if line.startswith(tuple(ALPHA)):
    pass

Of course, for this simple case, a regex test or the in operator would be more readable.

Solution 3

An easy solution would be to use the python regex module:

import re
if re.match("^[a-zA-Z]+.*", line):
   Do Something

Solution 4

This is probably the most efficient method:

if line != "" and line[0].isalpha():
    ...

View more solutions

Comments

[Dave Kirby]

-1: Using regex is massively overkill for this task. Also you only need to check the first character - this regex will try and match the whole string, which could be very long.

[John Machin]

Even if you were forced to use the re module, all you needed was [a-zA-Z]. The ^ is a waste of a keystroke (read the docs section about the difference between search and match). The + is a minor waste of time (major if the string has many letters at the start); one letter is enough. The .* is a waste of 2 keystrokes and possibly a lot more time.

[Will Hardy]

Even shorter: if line[:1].isalpha():

[teggy]

@Will What is the difference between your answer and if line[0].isalpha():

[dan04]

@teggy: The difference is that if line is an empty string, line[:1] will evaluate to an empty string while line[0] will raise an IndexError.

[DaveTheScientist]

I did not know that. +1 not for the best answer for this question, but because that is by far the best answer for a ton of my own code. Thank you.