Python: Unpacking an inner nested tuple/list while still getting its index number
11,237
for i, (letter, word) in enumerate(seq_nested):
print i, letter, word
Author by
Kit
Updated on June 06, 2022Comments
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Kit almost 2 years
I am familiar with using
enumerate()
:>>> seq_flat = ('A', 'B', 'C') >>> for num, entry in enumerate(seq_flat): print num, entry 0 A 1 B 2 C
I want to be able to do the same for a nested list:
>>> seq_nested = (('A', 'Apple'), ('B', 'Boat'), ('C', 'Cat'))
I can unpack it with:
>>> for letter, word in seq_nested: print letter, word A Apple B Boat C Cat
How should I unpack it to get the following?
0 A Apple 1 B Boat 2 C Cat
The only way I know is to use a counter/incrementor, which is un-Pythonic as far as I know. Is there a more elegant way to do it?
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michaelsnowden over 7 years@MadPhysicist Yes