Python - use list as function parameters

Question

How can I use a Python list (e.g. params = ['a',3.4,None]) as parameters to a function, e.g.:

def some_func(a_char,a_float,a_something):
   # do stuff

Solution 1

You can do this using the splat operator:

some_func(*params)

This causes the function to receive each list item as a separate parameter. There's a description here: http://docs.python.org/tutorial/controlflow.html#unpacking-argument-lists

Solution 2

This has already been answered perfectly, but since I just came to this page and did not understand immediately I am just going to add a simple but complete example.

def some_func(a_char, a_float, a_something):
    print a_char

params = ['a', 3.4, None]
some_func(*params)

>> a

Solution 3

Use an asterisk:

some_func(*params)

Solution 4

You want the argument unpacking operator *.

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Comments

[inspectorG4dget]

Along those lines, you can also use a dictionary: def f(a, b, c): #do stuff. mydict = {'a':1, 'b':2, 'c':3} f(**mydict)