Python: while not Exception

Question

So I am aware you can use try/except blocks to manipulate the output of errors, like so:

try:
    print("ok")
    print(str.translate)
    print(str.foo)
except AttributeError:
    print("oops, found an error")

print("done")

...which gives the following output:

ok
<method 'translate' of 'str' objects>
oops, found an error
done

Now, is there a way to do the following with a while loop, like while not AttributeError, like this:

while not AttributeError:
    print("ok")
    print(str.translate)
    print(str.foo)
print("done")

which would give the same output as above, just without oops, found an error? This would reduce the need for except: pass type blocks, which are necessary but a little pointless if you have nothing to do in the except block.

I tried while not AttributeError and while not AttributeError(), which both just completely skip anything in the while block. So, is there a way to do this in Python?

Edit: This really isn't a loop per se, but the while block would run, and continue on if it encounters an error, and just continue on if it reaches the end.

Solution 1

Can you try something like:

while True:
    try:
        print("ok")
        print(str.translate)
        print(str.foo)
    except:
        break
print('done')

Solution 2

The following code will loop until it encounters an error.

while True:
  try:
    print("ok")
    print(str.translate)
    print(str.foo)
  except AttributeError:
    print("oops, found an error")
    break
  print("done")

Solution 3

You can use suppress() as an alternative to try/except/pass available for python 3.4+

from contextlib import suppress

while True:
    with suppress(AttributeError):
        print("ok")
        print(str.translate)
        print(str.foo)
    break
print('done')

Solution 4

You can nest while loop:

try:
    while True:
        print("ok")
        print(str.translate)
        print(str.foo)
except:
    pass
print('done')

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