R “argument is of length zero” in if(condition)
If data is a one dimension array (the binary data you showed is) rather then a matrix, vector, or other structure you can use length to find the row count. This code shows how to add a count based on matches with a one dimensional array (note I assume inc is a pascal like custom function).
data = c(1, 0, 0, 1, 1, 0)
outcome = c(0, 0, 1, 0, 1, 0)
count <- 0
for (i in 1:length(data))
{
if(outcome[i]==data[i]) {
count <- count + 1 #could then do inc(count) for package Hmisc
}
}
count
If your data is being returned as a matrix of vectors then try this code (same note on Hmisc).:
data <- read.table(text = "
0 1 0 1
0 0 1 1
1 1 0 0
1 0 1 0
0 1 0 1", header = FALSE)
data <- as.matrix(data)
outcome <- c(0, 0, 1, 0, 1)
count <- 0
for (i in 1:nrow(data))
{
if(!is.null(outcome[i]==data[i, 1])) {
count <- count + 1 #see first example
}
}
cat(count)
Note: nrow does return either an integer or NULL
sheffy17
Updated on June 04, 2022Comments
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sheffy17 almost 2 years
Very new to R, would appreciate if you could tell me what I’m doing wrong.
This was my initial code:
count <- 0 for (i in 1:nrow(data)) { if(outcome[i]==data[1,i]) inc(count) <- 1 #package Hmisc }
where outcome and data[1] are vectors with binary values eg. [1, 0, 0, 1, 1, 0..]
I got the result ‘argument is of length zero’ with the if statement. Tested it individually with rows that matched/mismatched, discovered that the result shows up only in the latter.
So I amended my code to:
count <- 0 for (i in 1:nrow(data)) { if(!is.null(outcome[i]==data[1,i])) inc(count) <- 1 #package Hmisc }
Now the value that count returned is the number of ‘for' iterations.
Doesn’t this mean R is NOT returning a null value for ANY mismatch in the new code?? How is this happening? Solutions please?