Reading in a string of unknown length from the console

11,750

Solution 1

Found this somewhere on the net long ago, its really useful:

#include <stdio.h>
#include <stdlib.h>

int main()
{
    unsigned int len_max = 128;
    unsigned int current_size = 0;

    char *pStr = malloc(len_max);
    current_size = len_max;

    printf("\nEnter a very very very long String value:");

    if(pStr != NULL)
    {
    int c = EOF;
    unsigned int i =0;
        //accept user input until hit enter or end of file
    while (( c = getchar() ) != '\n' && c != EOF)
    {
        pStr[i++]=(char)c;

        //if i reached maximize size then realloc size
        if(i == current_size)
        {
                        current_size = i+len_max;
            pStr = realloc(pStr, current_size);
        }
    }

    pStr[i] = '\0';

        printf("\nLong String value:%s \n\n",pStr);
        //free it 
    free(pStr);
    pStr = NULL;


    }
    return 0;
}

Solution 2

Use realloc() to allocate the buffer and extend it when it's full.

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11,750
JimR
Author by

JimR

Updated on June 08, 2022

Comments

  • JimR
    JimR about 2 years

    If I want to read in a string of arbitrary length from the command line, what's the best way of going about it?

    At the moment I'm doing this:

    char name_buffer [ 80 ];
    int chars_read = 0;
    while ( ( chars_read < 80 ) && ( !feof( stdin ) ) ) {
       name_buffer [ chars_read ] = fgetc ( stdin );
       chars_read++;
    }
    

    But what can I do if the string is longer than 80 characters? Obviously I could just initialise the array to a bigger number but I'm sure there must be a better way to give the array more space using malloc or something?

    Any hints would be great.