Reading numbers from a text file into an array in C
Solution 1
change to
fscanf(myFile, "%1d", &numberArray[i]);
Solution 2
5623125698541159
is treated as a single number (out of range of int
on most architecture). You need to write numbers in your file as
5 6 2 3 1 2 5 6 9 8 5 4 1 1 5 9
for 16 numbers.
If your file has input
5,6,2,3,1,2,5,6,9,8,5,4,1,1,5,9
then change %d
specifier in your fscanf
to %d,
.
fscanf(myFile, "%d,", &numberArray[i] );
Here is your full code after few modifications:
#include <stdio.h>
#include <stdlib.h>
int main(){
FILE *myFile;
myFile = fopen("somenumbers.txt", "r");
//read file into array
int numberArray[16];
int i;
if (myFile == NULL){
printf("Error Reading File\n");
exit (0);
}
for (i = 0; i < 16; i++){
fscanf(myFile, "%d,", &numberArray[i] );
}
for (i = 0; i < 16; i++){
printf("Number is: %d\n\n", numberArray[i]);
}
fclose(myFile);
return 0;
}
Solution 3
for (i = 0; i < 16; i++)
{
fscanf(myFile, "%d", &numberArray[i]);
}
This is attempting to read the whole string, "5623125698541159"
into &numArray[0]
. You need spaces between the numbers:
5 6 2 3 ...
Solution 4
Loop with %c to read the stream character by character instead of %d.
Solution 5
There are two problems in your code:
- the return value of
scanf
must be checked - the
%d
conversion does not take overflows into account (blindly applying*10 + newdigit
for each consecutive numeric character)
The first value you got (-104204697
) is equals to 5623125698541159
modulo 2^32
; it is thus the result of an overflow (if int
where 64 bits wide, no overflow would happen). The next values are uninitialized (garbage from the stack) and thus unpredictable.
The code you need could be (similar to the answer of BLUEPIXY above, with the illustration how to check the return value of scanf
, the number of items successfully matched):
#include <stdio.h>
int main(int argc, char *argv[]) {
int i, j;
short unsigned digitArray[16];
i = 0;
while (
i != sizeof(digitArray) / sizeof(digitArray[0])
&& 1 == scanf("%1hu", digitArray + i)
) {
i++;
}
for (j = 0; j != i; j++) {
printf("%hu\n", digitArray[j]);
}
return 0;
}
Vonti
Updated on July 13, 2021Comments
-
Vonti almost 3 years
I'm a programming noob so please bear with me.
I'm trying to read numbers from a text file into an array. The text file, "somenumbers.txt" simply holds 16 numbers as so "5623125698541159".
#include <stdio.h> main() { FILE *myFile; myFile = fopen("somenumbers.txt", "r"); //read file into array int numberArray[16]; int i; for (i = 0; i < 16; i++) { fscanf(myFile, "%d", &numberArray[i]); } for (i = 0; i < 16; i++) { printf("Number is: %d\n\n", numberArray[i]); } }
The program doesn't work. It compiles but outputs:
Number is: -104204697
Number is: 0
Number is: 4200704
Number is: 2686672
Number is: 2686728
Number is: 2686916
Number is: 2004716757
Number is: 1321049414
Number is: -2
Number is: 2004619618
Number is: 2004966340
Number is: 4200704
Number is: 2686868
Number is: 4200798
Number is: 4200704
Number is: 8727656
Process returned 20 (0x14) execution time : 0.118 s Press any key to continue.