Regular expression - replace special characters, except dot

Question

$('#price').keyup(function(){
        $('#price').val($('#price').val().replace(/[_\W]+/g, "-"));
})

See it live at: http://jsfiddle.net/2KRHh/6/.

This removes special characters, but how can I specify that it not replace dots?

Solution

Use this for the regex instead:

 /[^\w.]|_/g

It reads any character that is not either alpha-numerical (which includes underbars) or dot, or that is an under bar.

update
But this is perhaps little more readable:

/[^0-9a-zA-Z.]/g

Comments

[sigpwned]

I think you meant to add a "\" in the regular expression: /([^\w.])|_/g Also, why have you added a capture group around the [^\w.] character class?

[Horn Masgerter]

but this replace also digits. This should allow digit 0-9 and numbers

[Faust]

@sigpwned: the capture group is not necessary.

[Faust]

@Horn: the \w means any char that is a number or a letter or _, while the ^ at the beginning of the character class means anything that is not one of these, so this will not replace digits.

[Toto]

Reread the question, they want to replace special characters except dot, so hyphen has to be removed.