Remove patterns from string using bash

Question

I'm trying to remove some patterns from a file input string (parsing file line by line). Here is a sample string:

1: (10/17 12:49:31.175) - CONSTANT ID1 - CONSTANT ID2: RAW DATA OUT     > [0x00,0xa2,…,0x00] 

And I want the output to be something like the following:

(12:49:31.175): RAW DATA OUT : [0x00,0xa2,…,0x00]

I have been trying to use egrep or sed but no luck so far, just keep getting errors or some "unterminated substitute pattern" error. Here is and example of what I have tried:

echo $line | sed -e 's/.*\s\([0-9]*:[0-9]*:[0-9]*.[0-9]*\)'

Any help would be appreciated. I'm usually more of a batch file guy instead of bash on my Mac OS/X.

EDIT:

I should mention, I'm reading a file as such:

while read line
do

Then I want to perform any actions on line for every line in the file.

Solution

You can also call perl from bash. The -n arg makes it loop for each line. -e means the script is one line.

cat in.txt | perl -ne 's{.*(.*\().*? (.*) -.*(:.*?)\s\s+.*(\[.*)}{$1$2$3 : $4};'

Comments

[Chef Pharaoh]

This looks good but I keep getting "No such file or directory" error. I'm reading a file like so: while read line and then want to parse line for each line in the file.

[Chef Pharaoh]

Or now I'm getting s/([^ ] ...": bad flag in substitute command: ')'

[Chef Pharaoh]

Yup, this is exactly what I was looking for. I had an extra - in the CONSTANT ID so I had to add another -.* in there. Although, I was hoping not to use perl and more regular scripting commands.

[Chef Pharaoh]

Can I use this output to print to a file now? Haha, never mind, just a matter of using redirect.

[mikeserv]

Anyone trying to replicate your approach is going to be in for an ugly surprise if the <<DATA they feed sed has any shell special characters in it. If you do not quote the heredoc limiter the shell will perform any expansions it can on the contents.