Replace all instances of character in string in typescript?

Question

I'm trying to replace all full stops in an email with an x character - for example "[email protected]" would become "myxemail@emailxcom". Email is set to a string.
My problem is it's not replacing just full stops, it's replacing every character, so I just get a string of x's.
I can get it working with just one full stop, so I'm assuming I'm wrong on the global instance part. Here's my code:

let re = ".";
let new = email.replace(/re/gi, "x");

I've also tried

re = /./gi;
new = email.replace(re, "x");

If anyone can shed any light I'd really appreciate it, I've been stuck on this for so long and can't seem to figure out where I'm going wrong.

** Edit: Whoops, my new variable was actually called newemail, keyword new wasn't causing the issue!

Solution 1

Your second example is the closest. The first problem is your variable name, new, which happens to be one of JavaScript's reserved keywords (and is instead used to construct objects, like new RegExp or new Set). This means that your program will throw a Syntax Error.

Also, since the dot (.) is a special character inside regex grammar, you should escape it as \.. Otherwise you would end up with result == "xxxxxxxxxxxxxxxxxx", which is undesirable.

let email = "[email protected]"

let re = /\./gi;
let result = email.replace(re, "x");

console.log(result)

Solution 2

You can try split() and join() method that was work for me. (For normal string text) It was short and simple to implement and understand. Below is an example.

let email = "[email protected]";
email.split('.').join('x');

So, it will replace all your . with x. So, after the above example, email variable become myxemail@gmailxcom

Comments

[Rebecca]

I was going wrong with the /./gi, /\./ solved the issue! Thanks a million!

[George]

how to replace a character in a string based on index?

[gyre]

@George What do you mean? Can you give me a desired example/output?

[George]

let theString = "george" , i want to replace the third character for example theString[2]="a" so now it would be 'gearge'

[gyre]

in that case I would suggest: let string = 'george'; let result = string.slice(0, 2) + 'a' + string.slice(3);

[George]

thank you sounds good currently i am transforming it to array then do the change then transforming it to string i'll try your way asap

[Björn]

Do not forget that g to make the expression global. I always do.

[Ka Wai Cheung]

I think this should be the default approach for a basic search/replace over using any regex.

[Sanjay Verma]

This is brilliant!!