RESTEasy - @Path requiring a full path?

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Solution: add the following in your web.xml

<context-param>
    <param-name>resteasy.servlet.mapping.prefix</param-name>
    <param-value>/rest</param-value>
</context-param>

Where /rest is the beginning of your <url-pattern>/rest/*</url-pattern>

(Source: http://docs.jboss.org/resteasy/docs/2.0.0.GA/userguide/html/Installation_Configuration.html#d0e72)

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Bastien Jansen
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Bastien Jansen

Ceylon &amp; Java developer; Occasional blogger at https://bjansen.github.io

Updated on July 09, 2022

Comments

  • Bastien Jansen
    Bastien Jansen almost 2 years

    I was messing around with JAX-RS and made an application which calls REST services which produce JSON. I tried Jersey and everything went fine, but I had to switch to RESTEasy as my application needs to be built with JDK5. I changed my web.xml to something like this:

    <web-app>
    <context-param>
        <param-name>resteasy.scan</param-name>
        <param-value>true</param-value>
    </context-param>
    
    <listener>
        <listener-class>
         org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap
        </listener-class>
    </listener>
    
    <servlet>
        <servlet-name>RESTEasy</servlet-name>
        <servlet-class>org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>RESTEasy</servlet-name>
        <url-pattern>/rest/*</url-pattern>
    </servlet-mapping>
    <!-- ... -->
    </web-app>
    

    So I expect every URL starting with /rest to be handled by RESTEasy. My services are as follows:

    @Path("/services")
    public class MyRESTServices {
    
        @GET
        @Path("service1")
        @Produces(MediaType.APPLICATION_JSON)
        public Object service1(Blah blah) {
    
        }
    }
    

    This worked fine using Jersey, http://localhost/MyContext/rest/services/service1 was bound to my service1() method. When I change to RESTEasy, though, I had a 404:

    HTTP Status 404 - Could not find resource for relative : /rest/services/service1 of full path: http://localhost/MyContext/rest/services/service1

    Which means that RESTEasy handled the request but could not find any service bound to this URL.

    On my class, changing @Path("/services") to @Path("/rest/services") worked, though. Do you have any idea why I got this strange behaviour? All the tutorials/docs I read mentionned only relative paths, not including the /rest prefix...

    • Donal Fellows
      Donal Fellows over 13 years
      How are you configuring RESTEasy internally? With CXF, I have to configure the removal of the /rest fragment in my Spring config file.
    • Bastien Jansen
      Bastien Jansen over 13 years
      I don't configure anything else that what you can see in the web.xml (scan for annotations). I'll see if the removal can be configured.
    • Bastien Jansen
      Bastien Jansen over 13 years
      Shame on me, it was right in front of me in the docs: "The resteasy.servlet.mapping.prefix <context param> variable must be set if your servlet-mapping for the Resteasy servlet has a url-pattern other than /*"
    • fmucar
      fmucar over 13 years
      I dont think it is strange. Your regular expression does not mention anything about /rest path so resteasy cant know about it if you dont add it to regular exp or web.xml as a prefix.
  • bmauter
    bmauter over 10 years
    Thanks. Your "Where..." sentence is what straightened me out. I was using /rest/* in the param-value element.
  • 09Q71AO534
    09Q71AO534 over 9 years
    @Nebelmann I want to have my url "http://localhost:8080/MyContent/rest/services/service1" as "http://localhost:8080/MyContent/services/service1" i dont want to have rest in my url pattern. Can you help me out how to define that