Return Type Boolean in Java
Solution 1
As @DR says, Java does not force you to assign the result of a method call. A void or non-void method call is valid as a complete statement in Java.
I would surmise that the reasons Java is designed this way include the following:
Convenience: most developers would find it a nuisance if the result of every non-void method call had to be assigned.
Tradition: C, C++ and almost no other language force you to do this. (I have vague recollections of some language that did ... but that was long ago.)
Futility: you cannot stop the developer from assigning the result to a temporary variable and then ignoring it. Or writing a wrapper method that does the same thing.
Better alternatives: if you want to encourage the developer to pay attention to an error in Java, throw an appropriate checked exception.
Solution 2
Java never forces you to assign the return value of a function call. There must be something wrong with your other code (you might post it here, too)
PS: This reminds me of good old Turbo Pascal, where you had to enable the Extended Syntax to get this behaviour.
gmhk
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Updated on September 17, 2020Comments
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gmhk over 3 years
I have a question on
boolean
return types. Check the following code:Code Sample 1
boolean flag = sampleMethod(); public boolean samplemethod(){ return false; }
Code Sample 2
sampleMethod(); public boolean samplemethod(){ return false; }
In the above two examples, the code compiles properly without any compile time or run time exceptions. My doubt is, Java doesn't make it mandatory for the
boolean
return type to be assigned in the calling program, where for the other data types the program does not work. Can you please explain the reason for this to me? -
gmhk about 14 yearsI am not focusing on whether it compiles or not, main question is the calling program doesnot make it mandatory to assign the return boolean value from the method.
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Bozho about 14 yearsthe answer was pretty clear that Java never forces you to assign the return value.
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Nyerguds over 12 yearsThis still doesn't compile unless
sampleMethod();
is called from inside an actual function though. Otherwise it's seen as illegal function definition without a return type set. -
Saurabh over 12 years@Nyerguds, of course. I assume it is obvious from context that the call to
sampleMethod();
is within another method somewhere. The same applies to the code sample in the question.