Round a decimal to the nearest quarter in C#
Solution 1
Multiply it by four, round it as you need to an integer, then divide it by four again:
x = Math.Round (x * 4, MidpointRounding.ToEven) / 4;
The various options for rounding, and their explanations, can be found in this excellent answer here :-)
Solution 2
Alternatively, you can use UltimateRoundingFunction given in this blog: http://rajputyh.blogspot.in/2014/09/the-ultimate-rounding-function.html
//amountToRound => input amount //nearestOf => .25 if round to quater, 0.01 for rounding to 1 cent, 1 for rounding to $1 //fairness => btween 0 to 0.9999999___. // 0 means floor and 0.99999... means ceiling. But for ceiling, I would recommend, Math.Ceiling // 0.5 = Standard Rounding function. It will round up the border case. i.e. 1.5 to 2 and not 1. // 0.4999999... non-standard rounding function. Where border case is rounded down. i.e. 1.5 to 1 and not 2. // 0.75 means first 75% values will be rounded down, rest 25% value will be rounded up. decimal UltimateRoundingFunction(decimal amountToRound, decimal nearstOf, decimal fairness) { return Math.Floor(amountToRound / nearstOf + fairness) * nearstOf; }
Call below for standard rounding. i.e. 1.125 will be rounded to 1.25
UltimateRoundingFunction(amountToRound, 0.25m, 0.5m);
Call below for rounding down border values. i.e. 1.125 will be rounded to 1.00
UltimateRoundingFunction(amountToRound, 0.25m, 0.4999999999999999m);
So called "Banker's Rounding" is not possible with UltimateRoundingFunction, you have to go with paxdiablo's answer for that support :)
handles
Updated on July 09, 2022Comments
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handles almost 2 years
Is there a simple way in c# to round a decimal to the nearest quarter i.e. x.0, x.25, x.50 x.75 for example 0.21 would round to 0.25, 5.03 would round to 5.0
Thanks in advance for any help.
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joelc about 6 yearsThis is exactly what I needed to round to the nearest n.
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Jesus is Lord over 2 yearsI wrote this answer as an extension method: