round decimal values up to the nearest of 0.01?

c# numbers rounding

14,396

Solution 1

Math..::.Round Method (Decimal, Int32, MidpointRounding)

Rounds a double-precision floating-point value to the specified number of fractional digits. A parameter specifies how to round the value if it is midway between two other numbers.

   Math.Round(1.489,2,MidpointRounding.AwayFromZero)

Solution 2

Did you try

 Math.Round(16.482*200)/200;

14,396

Author by

RameshVel

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Updated on June 04, 2022

Comments

RameshVel almost 2 years
Possible Duplicate:
c# - How do I round a decimal value to 2 decimal places (for output on a page)

How to round decimal value up to nearest 0.05 value??, the linked SO post also discusses the similar topic, but its not the output i expected.

I need to convert the decimal values like this
```
16.489-->16.49
16.482-->16.48
16.425-->16.43
7.67 --> 7.67 (no conversion)
```
I can use the below C# method to convert the values
```
  Math.Round(16.482*20)/20;
```
But this method not works for me, it gives the following results
```
16.489-->16.5 
16.482-->16.5 
7.67 --> 7.7
16.425-->16.45 
```
whats the elegant way in c# to do this.
Ben S about 14 years

There isn't a cleaner way to do this?
Ashith about 14 years

I have no idea, I don't know C#. I just know how the example code works. It just multiples the number by the inverse of where you want to round, and then divides that sum by the same inverse to get back to the same number. You can use the same idea to round to the nearest quarter (which is how I learned this trick).
Ashith about 14 years

You could create a function that you plug the value and what you want to round off to, but since the SO didn't seem to realize that he wants to round off to .005, I'm not sure that would have been helpful to suggest.
RameshVel about 14 years

@Anthony, i tried that too. its not working on 16.425 or 16.124.
Ashith about 14 years

@Ramesh, did it work for the others?
RameshVel about 14 years

@Anthony, yes it works on other scenarios..
Ashith about 14 years

I see, you want to round to the nearest .01, not .05 or .005. So you should do Math.Round(16.482*100)/100;. Let me know if that gives trouble.
Ashith about 14 years

What if you want to round to the nearest quarter? so that 1.489 rounds to 1.5, but 1.479 rounds to 1.475?
RameshVel about 14 years

@Anthony, yes it works now after specifying 100. thanks
mrnakumar about 14 years

Math.Round(1.479,2,MidpointRounding.AwayFromZero) round to 1.48
RameshVel about 14 years

@Fredou, it works fine.. thanks...
Ashith about 14 years

But I don't want to round to 1.48 in that example, I wan to round to 1.475. I want the last two digits to round to 0, 25, 5, or 75, depending on what is closest.
mrnakumar about 14 years

@anthony, I'm half asleep but... this should do it ? (decimal)(int)(decimal)(1.479*100)/100+(Math.Round((decimal)‌1.479,2,MidpointRoun‌ding.AwayFromZero) - (decimal)1.479 )/2*10
Ashith about 14 years

Fredou, Hey man, I really appreciate the time. I was really trying to make a case for using the inverse method that the user was originally trying to use and that I was showing how to adapt. But I'm really blown away that you figured that out. Get some sleep, buddy.