Send file from client to server using XMLRPC?
10,333
Solution 1
Server side:
def server_receive_file(self,arg):
with open("path/to/save/filename", "wb") as handle:
handle.write(arg.data)
return True
Client side:
with open("path/to/filename", "rb") as handle:
binary_data = xmlrpclib.Binary(handle.read())
client.server_receive_file(binary_data)
This worked for me.
Solution 2
You want to look into the xmlrpclib Binary object. With this class you can encode and decode to/from a base64 string.
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Author by
user311703
Updated on June 04, 2022Comments
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user311703 almost 2 years
I want to write Python code to send a file from client to server. server needs to save the file sent from the client. But my code have some bugs which I cannot fix. Below is my server code:
# server.py from SimpleXMLRPCServer import SimpleXMLRPCServer import os server = SimpleXMLRPCServer(('localhost', 9000)) def save_data(data): handle = open("x123.dat", "wb") handle.write(data) handle.close() server.register_function(save_data, 'save_data') server.serve_forever()
And the client code:
# client.py import sys, xmlrpclib proxy = xmlrpclib.Server('http://localhost:9000') handle = open(sys.argv[1], "rb") proxy.save_data(handle.read()) handle.close()
But then I run my code, the client returns the following error (this is on Windows):
Traceback (most recent call last): File "client.py", line 6, in <module> proxy.save_data(handle.read()) File "c:\python27\lib\xmlrpclib.py", line 1224, in __call__ return self.__send(self.__name, args) File "c:\python27\lib\xmlrpclib.py", line 1575, in __request verbose=self.__verbose File "c:\python27\lib\xmlrpclib.py", line 1264, in request return self.single_request(host, handler, request_body, verbose) File "c:\python27\lib\xmlrpclib.py", line 1297, in single_request return self.parse_response(response) File "c:\python27\lib\xmlrpclib.py", line 1473, in parse_response return u.close() File "c:\python27\lib\xmlrpclib.py", line 793, in close raise Fault(**self._stack[0]) xmlrpclib.Fault: <Fault 1: "<class 'xml.parsers.expat.ExpatError'>:not well-formed (invalid token): line 7, column 1">
I have some questions:
How to fix the above bug?
My code needs to transfer some big files sometimes. Since my method is so simple, I doubt that it is efficient for moving big data. Could anybody please suggest a better method to move big files? (Of course it is better to use XMLRPC on Python)