Shell script - Find files modified today, create directory, and move them there

Question

I was wondering if there is a simple and concise way of writing a shell script that would go through a series of directories, (i.e., one for each student in a class), determine if within that directory there are any files that were modified within the last day, and only in that case the script would create a subdirectory and copy the files there. So if the directory had no files modified in the last 24h, it would remain untouched. My initial thought was this:

#!/bin/sh
cd /path/people/ #this directory has multiple subdirectories

for i in `ls`
do
   if find ./$i -mtime -1  -type f  then 
     mkdir ./$i/updated_files
     #code to copy the files to the newly created directory
   fi
done

However, that seems to create /updated_files for all subdirectories, not just the ones that have recently modified files.

Solution 1

Heavier use of find will probably make your job much easier. Something like

find /path/people -mtime -1 -type f -printf "mkdir --parents %h/updated_files\n" | sort | uniq | sh 

Solution 2

The problem is that you are assuming the find command will fail if it finds nothing. The exit code is zero (success) even if it finds nothing that matches.

Something like

UPDATEDFILES=`find ./$i -mtime -1  -type f`
[ -z "$UPDATEDFILES" ] && continue
mkdir ...
cp ...
...

Comments

[Everaldo Aguiar]

Thanks. This statement works fine for creating the subfolders :) How would I incorporate a statement that copies multiple recently modified files into the folder just created? Does find give me a flag holding the list of files found?

[cili]

@Everaldo Aguiar: Can you post the solution here, please?