Shellscript Read XML attribute value
Solution 1
You can use a proper XML parser like xmllint. If your version supports xpath, it will be very easy to grab specific values. If it doesn't support xpath, then you can use --shell
option like so:
$ echo 'cat //properties/property[@name="abc"]/@value' | xmllint --shell myxml
/ > -------
value="15"
/ >
You can then use awk
or sed
to format and extract desired field from output.
$ echo 'cat //properties/property[@name="abc"]/@value' | xmllint --shell myxmlfile | awk -F'[="]' '!/>/{print $(NF-1)}'
15
You can use command substitution to capture the output in a variable by saying:
$ myvar=$(echo 'cat //properties/property[@name="abc"]/@value' | xmllint --shell myxml | awk -F'[="]' '!/>/{print $(NF-1)}')
$ echo "$myvar"
15
Using anything else other than a xmlparser is prone to errors and will break easy.
Solution 2
quick and dirty
sed -n '/<Properties>/,\|</properties>| {
s/ *<property name="xyz" value="\([^"]*\)"\/>/\1/p
}'
no xml check and based on your sample so assume same structure (one property name per line, ...)
posix version (--posix
for GNU sed)
patel kavit
I am a mobile application developer. worked for Symbian, iOS & Windows Phone.
Updated on June 12, 2022Comments
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patel kavit almost 2 years
We want to read XML attributes from an XML file. Example of file content is as below:
<properties> <property name="abc" value="15"/> <property name="xyz" value="26"/> </properties>
We want to read value (i.e. 15) for property "abc" using shell script.
Please suggest shell commands to achieve this.