show hidden div section based on if statement

Question

I have a few hidden divs on page like this

<div class="form" id="scheduler" style="display: none;">

<div class="form" id="test" style="display: none;">

<div class="form" id="super" style="display: none;">

I would like a jscript which can be called to show these hidden divs based on criteria like this

<?php 
if ($_GET['id'] == 'scheduler') {
   call jscript function (show div id:scheduler in this case)
}
else if ($_GET['id'] == 'test') {
   call jscript function (show div id:test in this case)
}
else if ($_GET['id'] == 'super') {
   call jscript function (show div id:super in this case)
}
?>

thanks.

Solution

you cannot call javascript function from PHP, PHP is server side based and stands for Preprocesing Hypertext while Javascript is browser based.

You could use:

<?php 
    if ($_GET['id'] == 'scheduler') {
       $showdiv = 'scheduler';
    }
    else if ($_GET['id'] == 'test') {
       $showdiv = 'test';
    }
    else if ($_GET['id'] == 'super') {
       $showdiv = 'super';
    }
    echo "<script type=\"text/javascript\">document.getElementById('".$showdiv."').style.display = 'block';</script>";
?>

but that should be at bottom of the page, after those divs are loaded.

Comments

[php_javascript_html_dev]

ahh! Mihai > you just killed it just what i wanted after lot of head banging.. thanks much