Simplest method of asking user for password using graphical dialog in Python?

15,976

Solution 1

from Tkinter import *

def getpwd():
    password = ''
    root = Tk()
    pwdbox = Entry(root, show = '*')
    def onpwdentry(evt):
         password = pwdbox.get()
         root.destroy()
    def onokclick():
         password = pwdbox.get()
         root.destroy()
    Label(root, text = 'Password').pack(side = 'top')

    pwdbox.pack(side = 'top')
    pwdbox.bind('<Return>', onpwdentry)
    Button(root, command=onokclick, text = 'OK').pack(side = 'top')

    root.mainloop()
    return password

Solution 2

Because you asked for the simplest (Python 2.7):

import Tkinter, tkSimpleDialog
tkSimpleDialog.askstring("Password", "Enter password:", show='*')

For Python 3.3:

import tkinter
tkinter.simpledialog.askstring("Password", "Enter password:", show='*')

For Python 3.6+:

import tkinter as tk
import tkinter.simpledialog
tk.Tk().withdraw()
tkinter.simpledialog.askstring("Password", "Enter password:", show='*')

Solution 3

Because not everyone wants to use TK, here's a script using PyQt:

from PyQt5.QtWidgets import QApplication, QInputDialog, QLineEdit
import sys
app = QApplication(sys.argv)
qd = QInputDialog()
qd.setTextEchoMode(QLineEdit.Password)
qd.show()
app.exec()

And, because you wouldn't usually just ask a user for a password just for the heck of it:

#!/bin/env python3
#passwordPrompt.py

from PyQt5.QtWidgets import QApplication, QInputDialog
import sys, time

def succFunc():
  sys.stdout.write(qd.textValue())
  sys.stdout.flush()
  exit(0)

def failFunc():
  exit(1)

app = QApplication(sys.argv)
qd = QInputDialog()
#QLineEdit.Password
qd.setTextEchoMode(2)
qd.rejected.connect(failFunc)
qd.accepted.connect(succFunc)
qd.show()
app.exec()

And the corresponding bash function:

#!/bin/bash

passwordPrompt.py | tee

Solution 4

Expanding on Diego's answer with some minimal housekeeping (without this I was getting crashes galore trying to use his beautifully brief example):

import Tkinter, tkSimpleDialog 
root = Tkinter.Tk() # dialog needs a root window, or will create an "ugly" one for you
root.withdraw() # hide the root window
password = tkSimpleDialog.askstring("Password", "Enter password:", show='*', parent=root)
root.destroy() # clean up after yourself!

This will work well from a program that is otherwise just a terminal / console application.

Solution 5

Resolved scoping issues of @pycoder112358 post:

from tkinter import *

PASSWORD = ''

def get_passwd():
    global PASSWORD
    root = Tk()
    pwdbox = Entry(root, show = '*')

    def onpwdentry(evt):
        global PASSWORD 
        PASSWORD = pwdbox.get()
        root.destroy()
    def onokclick():     
        global PASSWORD
        PASSWORD = pwdbox.get()
        root.destroy()

    Label(root, text = 'Password').pack(side = 'top')

    pwdbox.pack(side = 'top')
    pwdbox.bind('<Return>', onpwdentry)
    Button(root, command=onokclick, text = 'OK').pack(side = 'top')

    root.mainloop()
    return PASSWORD
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liamzebedee
Author by

liamzebedee

Software engineer with design-thinking mindset. Always learning, started programming when I was 11, moved to Sydney when I was 17, been working/learning since.

Updated on July 26, 2022

Comments

  • liamzebedee
    liamzebedee almost 2 years

    I'm developing a backup daemon that will run silently in the background. The daemon relies on the duplicity backup software, which when backing up requires an encryption key. I cannot ask for the password through the console because obviously, the daemon has no access to such.

    How could I easily create a prompt that asks the user to type in a password, and returns it to the application (through a Python variable)? I'm using Python 2.7.

  • liamzebedee
    liamzebedee about 11 years
    Doesn't work for me. I fixed an issue with root being referenced before defined. Now I can get the dialog to show, but when I type the password 1) the characters show, instead of black dots and 2) when I hit return nothing is returned from getpwd. Also, I get an error when I click OK - onpwdentry() takes exactly 1 argument Thanks for the quick response.
  • pycoder112358
    pycoder112358 about 11 years
    Ok, that last edit should fix your problems. For 1) I set the "show" property of the Entry widget to '*', so it'll show asterisks instead of letters. 2) was an incredibly stupid error on my part: I had the subfunction returning the password, when I obviously wanted the main function returning it. mainloop() is blocking, so the password won't be returned until the window is destroyed by onokclick() or onpwdentry()
  • liamzebedee
    liamzebedee about 11 years
    Thanks, just fixed the last bug, which was modifying the password outside its scope, which meant that the method was still returning "". Added a nonlocal hack for Python 2.x (using dict), and it successfully works!
  • pycoder112358
    pycoder112358 about 11 years
    Glad to help! Sorry about all the errors the first two edits; I don't seem to be thinking too well tonight.
  • Mallikarjunarao Kosuri
    Mallikarjunarao Kosuri about 8 years
    @pycoder112358 still scoping issue are there i have updated with procedure at the bottom
  • eztam
    eztam over 7 years
    For me this is the best solution since I'm having a console application. But how to open the dialog window on the main screen, when having multiple screens on Linux? The solution from @pycoder112358 opens the dialog on the main screen.
  • ryry1985
    ryry1985 about 7 years
    For Python 3.3: import tkinter tkinter.simpledialog.askstring("Password", "Enter password:", show='*')
  • Andreas H.
    Andreas H. over 5 years
    Seems only to work, if you initialize Tk() first, without it fails with 'NoneType' object has no attribute 'winfo_viewable'. At least in Python 3.6
  • Pedro Lobito
    Pedro Lobito almost 4 years
    You only need to use global inside onpwdentry() and onokclick().