Sort Tuples Python

Question

I have a list of tuples in my Blender python code

scores=[(1489,"Sean"), (2850,"Bob"), (276,"Crap Player"), (78495, "Great Player"), (8473, "Damian"), (4860, "Andy"), (0, "Stephen")]

I'm trying to sort them by their score by using this

sorted(scores, key=lambda score: score[0], reverse=True)

but this is not working. I have no idea why. Any tips?

I've considered maybe a better implementation is to create a new Score class with fields name and score

EDIT:

Thanks guys for the fast reply

it was giving me no errors with the sorted method but was not sorting. I used the sort() and it works.

I think python is just a little weird in Blender maybe?

Thanks!

Solution 1

Just do:

print sorted(scores, reverse=True)
[(78495, 'Great Player'), (8473, 'Damian'), (4860, 'Andy'), (2850, 'Bob'), (1489, 'Sean'), (276, 'Crap Player'), (0, 'Stephen')]

you can use scores.sort(reverse=True) if you want to sort in place, and by the way the sort function in case of list of tuple by default sort by first item , second item ..

Solution 2

sorted() returns the sorted sequence. If you want to sort a list in place then use list.sort().

Comments

[Robert Hensing]

This will also sort players with identical scores alphabetically, which might be desirable.

[code_dredd]

@RobertHensing Is there a way to get sorted to not sort by the 2nd key (i.e player names)? Docs say that sorted is guaranteed to be stable, so it should be preserving the original order when the 1ary keys being compared are equal, but it doesn't.

[code_dredd]

In that case, you actually have to use the key function explicitly. For example: sorted(scores, reverse=True, key=lambda s: s[0])

[uuu777]

I have three parameters to sort 2 strings and numerical value - what should I do, write function that produces concatenated string of some sort and then compare these strings????