Sorting of an array alphabetically in swift

Question

I am new to swift.I am trying one sample app in which I need to implement the sorting of an array in alphabetical order.I getting the json data and I am adding the titles in the array.Now i would like to sort that alphabetically.Here is my code .....

func updateSearchResults(data: NSData?)
{
    do
    {
            let json = try NSJSONSerialization.JSONObjectWithData(data!, options: .AllowFragments)

            if let blogs: NSArray = json["results"] as? [AnyObject] {
                print(blogs)
                for blog in blogs {
                    if let name = blog["original_title"] as? String {
                        names.addObject(name)
                    }
                }
                print(names)
                **let sortedArray = sorted(names, {
                (str1: String, str2: String) -> Bool in
                return str1.toInt() < str2.toInt()** // Here I am getting the Error Message
                })

            }
    }
    catch {
        print("error serializing JSON: \(error)")
    }
}

The error message I am getting is "Cannot invoke 'sorted' with an argument list of type '(NSMutableArray, (String, String) -> Bool)'"

I tried a lot to achieve this but I didn't find the solution. Can anyone help me to resolve this issue. Thanks In Advance.

Solution 1

First convert NSMutableArray to the Array by using below line of code.

let swiftArray = mutableArray as AnyObject as! [String]

Use below line of code to sort the Array.

var sortedArray = names.sorted { $0.localizedCaseInsensitiveCompare($1) == NSComparisonResult.OrderedAscending }

Check below link for sort Closures. https://developer.apple.com/library/ios/documentation/Swift/Conceptual/Swift_Programming_Language/Closures.html

Update for Swift 3.0

var sortedArray = swiftArray.sorted { $0.localizedCaseInsensitiveCompare($1) == ComparisonResult.orderedAscending }

Solution 2

Use this simple code of line to sort ur array

 let sortedNames = names.sort { $0.name < $1.name }

For Swift 4 you can use only this

let sortedNames = names.sorted(by: <)

Solution 3

Swift4

var names = [ "Alpha", "alpha", "bravo", "beta"]
var sortedNames = names.sorted { $0.localizedCaseInsensitiveCompare($1) == ComparisonResult.orderedAscending }
print(sortedNames) //Logs ["Alpha", "alpha","beta", "bravo"]

Solution 4

Swift 4(working code)

JSON response -> Stored in aryNameList

"DATA": [
{
        email = "[email protected]";
        firstname = Harvey
},
{
        email = "[email protected]";
        firstname = poonam
},
{
        email = "[email protected]";
        firstname = rahul
},
{
        email = "[email protected]";
        firstname = Chulbulx
},
{
        email = "[email protected]";
        firstname = rahul
},
{
        email = "[email protected]";
        firstname = Jay
},
{
        email = "[email protected]";
        firstname = Roy
},
{
        email = "[email protected]";
        firstname = Regan
},
{
        email = "[email protected]";
        firstname = Jaydip
}
]

Code

    self.aryNameList = self.aryNameList.sorted(by: { (Obj1, Obj2) -> Bool in
       let Obj1_Name = Obj1.firstname ?? ""
       let Obj2_Name = Obj2.firstname ?? ""
       return (Obj1_Name.localizedCaseInsensitiveCompare(Obj2_Name) == .orderedAscending)
    })

working every case (for ex: lowerCase, upperCase..)

Solution 5

For an array of objects:

items = items.sorted(by: { (item1, item2) -> Bool in
        return item1.product.name.compare(item2.product.name) == ComparisonResult.orderedAscending
    })

View more solutions

Comments

[jjatie]

Why are you choosing to use NSArray instead of a Swift Array?

[anusha hrithi]

It is showing the error like "Value of type 'NSMutableArray' has no member 'sorted'

[Admin]

@anushahrithi sorted was removed, use sort instead.

[Jigar]

you must pass an array of sort descriptors (even if it's only one): var descriptor: NSSortDescriptor = NSSortDescriptor(key: "name", ascending: true) var sortedResults: NSArray = results.sortedArrayUsingDescriptors([descriptor])

[Moin Shirazi]

@Kenneth Yes, in this scenario this will also work fine

[Admin]

Since names looks to have the type Array<String> it wouldn't have the property name. Your call should look like names.sort { $0 < $1 }. That can even be shorted to names.sort(<).

[jjatie]

This doesn't take into account capitalization (and likely other things when translating to other languages). For example "Bag" would come before "art".

[jjatie]

Also, you can now just write .sorted() to sort in ascending order.

[Moin Shirazi]

Thanks @jjatie ... You can edit the answer and update if you have verified and tested the code

[genaks]

You might want to use lowercased() for the names just in case :)

[Zaporozhchenko Oleksandr]

Don't u think that using let Obj1_Name = Obj1.firstname! like this is a bad idea? I mean any force unwrap of nil String can crash ur program)